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2 years ago

What's 209.54 in expanded form

Mathematics

2 answers:

irinina [24]2 years ago

6 0

I would guess it is
200+9 +.50+.04

Stella [2.4K]2 years ago

3 0

200 + 9 + 5 x 1/10 + 4 x 1/100.

I hope this helped you! Peace out! <3

- Hershey

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Find the exact solution of x 3x^2+7=28 A.+√7 B.7 C.+7 D.-7

yulyashka [42]

Answer:

x = ± $\sqrt{7}$

Step-by-step explanation:

3x² + 7 = 28 ( subtract 7 from both sides )

3x² = 21 ( divide both sides by 3 )

x² = 7 ( take square root of both sides )

x = ± $\sqrt{7}$

that is x = - $\sqrt{7}$ , x = $\sqrt{7}$

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2 years ago

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3 years ago

Find the values of a and b such that x^2-2x+2=(x-a)^2+b

vekshin1

Answer:

a = 1, b = 1

Step-by-step explanation:

Expand the right side and compare the coefficients of like terms on both sides, that is

right side

(x - a)² + b ← expand factor using FOIL

= x² - 2ax + a² + b

Compare to left side x² - 2x + 2

Compare the coefficients of the x- term

- 2a = - 2 ( divide both sides by - 2 )

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2 years ago

Calculate dy/dx if Ln (x + y) = e^x/y Pic included

vesna_86 [32]

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3 years ago

Please help! Simplify. Your answer should contain only positive exponents.

maxonik [38]

Answer:

$\frac{1}{4k^3}$

Step-by-step explanation:

It's already in a form that only ha positive exponents. Just to state it though you could rewrite it as $k*(4k^{4})^{-1}$ or $k*4^{-1}*k^{-4}$ The question asks for positive exponents though so yu don't need to do that.

You also need to know $\frac{x^a}{x^b}=x^{a-b}$ so in this case $\frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}$

so $\frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}$

3 0

2 years ago