Given that 8 <y< 12 and 1<x< 6, find the maximum possible value ofx+y/y-x

1 answer:

7 0

Answer:

Step-by-step explanation:

y = {9, 10, 11}

x = {2, 3, 4 , 5}

Maximum value of x + y = 11 + 5 = 16

Minimum value of y -x = 9 - 2 = 7

$\frac{x+y}{y-x}=\frac{16}{7}$

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Given that 8 <y< 12 and 1<x< 6, find the maximum possible value ofx+y/y-x​