Question 1- A circle is formed from the cross section of a plane and sphere
Question 2- A square is formed from the cross section of a plane and a cube
Question 3- A circle is formed from the cross section of a plane and cone
Question 4- A rectangle is formed from the cross section of a plane and rectangular pyramid.
Question 5- A circle is formed from the cross section of a plane and a cylinder
Answer:
x=9
Step-by-step explanation:
5( x + 7) - 3 ( x - 4) = 7x + 2
Distribute
5x+35 - 3x +12 = 7x +2
2x +47 = 7x+2
Subtract 2x from each side
2x+47-2x =7x -2x+2
47 = 5x+2
Subtract 2 from each side
47-2= 5x+2-2
45= 5x
Divide by 5
45/5 =5x/5
9 =x
Answer:
B. 21.2
Step-by-step explanation:
Perimeter of ∆ABC = AB + BC + AC
A(-4, 1)
B(-2, 3)
C(3, -4)
✔️Distance between A(-4, 1) and B(-2, 3):
AB = 4 units
✔️Distance between B(-2, 3) and C(3, -4):
BC = 8.6 units (nearest tenth)
✔️Distance between A(-4, 1) and C(3, -4):
AC = 8.6 units (nearest tenth)
Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units
<u>Finding x:</u>
We know that the diagonals of a rhombus bisect its angles
So, since US is a diagonal of the given rhombus:
∠RUS = ∠TUS
10x - 23 = 3x + 19 [replacing the given values of the angles]
7x - 23 = 19 [subtracting 3x from both sides]
7x = 42 [adding 23 on both sides]
x = 6 [dividing both sides by 7]
<u>Finding ∠RUT:</u>
We can see that:
∠RUT = ∠RUS + ∠TUS
<em>Since we are given the values of ∠RUS and ∠TUS:</em>
∠RUT = (10x - 23) + (3x + 19)
∠RUT = 13x - 4
<em>We know that x = 6:</em>
∠RUT = 13(6)- 4
∠RUT = 74°
3.10/155= 0.02 } subtract = 0.07 more
7.65/85= 0.09 }
