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2 years ago

Please complete the system of equations.

Mathematics

1 answer:

kogti [31]2 years ago

8 0

Answer:

x=-1,y=0

Step-by-step explanation:

-10y+9x=-9

10y+5x=-5

14x=-14

x=-1

-10y-9=-9

y=0

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The scatter plot below shows the relationship between drop height and speed of a roller coaster.

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Step-by-step explanation:

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3 years ago

Rewrite the quadratic funtion from standard form to vertex form. <br><br> F(x)=2x^2-20x+26

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F(x)=2(x-5)^2-24 simple algebra

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3 years ago

What is the measure of AC ?<br> Enter your answer in the box.

elena55 [62]

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3 years ago

Willy Wonka has 2 candies, Wonka bars and Everlasting Gobstoppers. Both have both natural sugar and sucrose in them. Each Wonka

love history [14]

Answer:

Wonka bars=3 and Everlasting Gobstoppers=24

Step-by-step explanation:

let the wonka bars be X

and everlasting gobstoppers be Y

the objective is to

maximize 1.3x+3.2y=P

subject to constraints

natural sugar

4x+2y=60------1

sucrose

x+3y=75---------2

x>0, y>0

solving 1 and 2 simultaneously we have

4x+2y=60----1

x+3y=75------2

multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have

4x+2y=60

4x+12y=300

-0-10y=-240

10y=240

y=240/10

y=24

put y=24 in equation 2 we have'

x+3y=75

x+3(24)=75

x+72=75

x=75-72

x=3

put x=3 and y=24 in the objective function we have

maximize 1.3x+3.2y=P

1.3(3)+3.2(24)=P

3.9+76.8=P

80.7=P

P=$80.9

8 0

3 years ago

The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability tha

kozerog [31]

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

$\mu = 3500 \times 0.0004 = 1.4$

The probability that 2 or fewer cars will be stolen is:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466$

$P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452$

$P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417$

Then:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335$

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

4 0

1 year ago