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grin007 [14]
3 years ago
8

Six less than the sum of 8 and 5

Mathematics
2 answers:
NARA [144]3 years ago
8 0
It would be:  8+5 - 6 = 13-6 = 7

So, Final Answer is 7

Hope this helps!
aniked [119]3 years ago
3 0
First you add 8+5 because there the sum and subtract 6 13-6=7


So it's 7
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A college student is taking two courses. The probability she passes the first course is 0.67. The probability she passes the sec
andrezito [222]

Answer:

0.58 = 58% probability she passes both courses

Step-by-step explanation:

We can solve this question treating the probabilities as a Venn set.

I am going to say that:

Event A: She passes the first course.

Event B: She passes the second course.

The probability she passes the first course is 0.67.

This means that P(A) = 0.67

The probability she passes the second course is 0.7.

This means that P(B) = 0.7

The probability she passes at least one of the courses is 0.79.

This means that P(A \cup B) = 0.79

a. What is the probability she passes both courses

This is P(A \cap B).

We use the following relation:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.67 + 0.7 - 0.79 = 0.58

0.58 = 58% probability she passes both courses

5 0
3 years ago
Simplify the complex fraction: 4/(x+3)/(1/x+3)
sertanlavr [38]

Answer:

4

Step-by-step explanation:

To simplify

\frac{4}{x+3} ÷ \frac{1}{x+3}

Change division to multiplication and turn the second fraction upside down, that is

\frac{4}{x+3} × \frac{x+3}{1}

Cancel the factor (x + 3) on the numerator/ denominator , leaving

\frac{4}{1} = 4

7 0
3 years ago
Read 2 more answers
Help please 50 points! Statistics Exam. it is timed
dlinn [17]

Answer:

The answer is C I believe.

Step-by-step explanation:

3 0
3 years ago
If F(x) = x² + 5x and G(x) = 2x + 1, find F(5) + G(6).
kondor19780726 [428]
F(x) = x^2 + 5x
F(5) = 5^2 + 5(5)
F(5) = 25 + 25
F(5) = 50

G(x) = 2x + 1
G(6) = 2(6) + 1
G(6) = 12 + 1
G(6) = 13

F(5) + G(6) = 50 + 13 = 63 <==
7 0
4 years ago
SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school are given below
kvasek [131]

Answer:

The value of test statistics is 25.

Step-by-step explanation:

We are given below the SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school;

380, 520, 480, 510, 560, 630, 670, 490, 500, 550, 400, 350, 440, 490, 620, 660, 700, 730, 740, 560

<em>Let </em>\sigma<em> = population standard of the reading and writing section SAT score of the students in this school</em>

So, Null Hypothesis, H_0 : \sigma \leq 100     {means that the reading and writing section SAT score of the students in this school is lesser than or equal to 100}

Alternate Hypothesis, H_A : \sigma<em> </em>> 100     {means that the reading and writing section SAT score of the students in this school is higher than 100}

The test statistics that would be used here is <u>One-sample Chi-square</u> test statistics;

                        T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2} __n_-_1

where, s^{2} = sample variance =  \frac{\sum (X-\bar X)^{2} }{n-1}  = 13135.8

            n = sample of 11th-grade students = 20

So, <u><em>the test statistics</em></u>  =  \frac{(20-1)\times 13135.8^{2} }{100^{2} }

                                     =  24.96 ≈ 25

Hence, the value of test statistics is 25.

5 0
4 years ago
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