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tamaranim1 [39]
3 years ago
11

Simplify the complex fraction: 4/(x+3)/(1/x+3)

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

4

Step-by-step explanation:

To simplify

\frac{4}{x+3} ÷ \frac{1}{x+3}

Change division to multiplication and turn the second fraction upside down, that is

\frac{4}{x+3} × \frac{x+3}{1}

Cancel the factor (x + 3) on the numerator/ denominator , leaving

\frac{4}{1} = 4

Alexandra [31]3 years ago
7 0

Answer:

The answer is 4, because the (x+3) cancels out.

Step-by-step explanation:

4/(x+3) / (1/x+3) =

The numerator will be multiplied by the inverse of the denominator:

4/(x+3) * (x+3)/1 =

Cross out the (x+3) in the numerator and the denominator.

What remains is:

4 / 1 = 4

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Condense the following logarithm: 5log_4(a) - 6log_4(b)​
grin007 [14]

Hi there! We are given the expression:

\large \boxed{5 log_{4}(a)  - 6 log_{4}(b) }

To condense or simplify the following logarithm. You have to remember these properties:

Properties - Logarithm

\large{ log_{b}(a)^{n}  = n log_{b}(a) } \\  \large{ log_{b}(a)  -  log_{b}(c)  =  log_{b}( \frac{a}{c} ) }

These two properties are what we need for our problem. Therefore,

\large{ log_{4}(a)^{5}  -  log_{4}(b)^{6} }

We use the log_b(a)^n = nlog_b(a) property to convert in the form above. Next, we use the second property.

\large{ log_{4}( \frac{ {a}^{5} }{ {b}^{6} } ) }

Answer

  • log base 4 of (a^5/b^6) is our simplifed form.

Any questions can be asked through comment as I may reply soon. Thanks for using Brainly! Have a good day and happy learning! :)

6 0
3 years ago
How do I find the value of x?
3241004551 [841]
The value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result.
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Find the slope of the line through each pair of points <br><br><br><br><br>(-20,-4), (-12,-10)​
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Answer:

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Step-by-step explanation:

i think. if not correct me

5 0
3 years ago
Read 2 more answers
Y = 5x – 1
AnnyKZ [126]
Y=5x-1
-15x-3y=3
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Answer:

Step-by-step explanation:

Subset of A = { {} , {a} , {b}, {a.b} }

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