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natka813 [3]
3 years ago
10

Could somebody please help me understand this?!?!? (y+1)=3/5(x-3)

Mathematics
2 answers:
nirvana33 [79]3 years ago
7 0
What we wanna do is flip this equation. Assuming we are solving for x

\frac{3}{5}x  +  \frac{-9}{5} = y + 1 < Flipped

Add 9/5 to both sides!

\frac{3}{5}x +  \frac{-9}{5} +  \frac{9}{5}  = y + 1 +  \frac{9}{5}  &#10;&#10; \frac{3}{5}x = y +  \frac{14}{5}

Then we wanna divide both sides by 3/5

\frac{3}{5}x/ \frac{3}{5} = y +  \frac{14}{5}/ \frac{3}{5}&#10;&#10;x =   \frac{5y + 14}{3}
bazaltina [42]3 years ago
6 0
I hope this helps you

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The value of the proposition is FALSE

Step-by-step explanation:

~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ ~X) v (B ⊃ X)]

Let's start with the smallest part: ~X. The symbol ~ is negation when X is true with the negation is false and vice-versa. In this case, ~X is true (T)

~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ T) v (B ⊃ X)]

Now the parts inside parenthesis:  (A ⊃ Y),(X ⊃ B),(A ≡ T) and (B ⊃ X). The symbol ⊃ is the conditional and A ⊃ Y is false when Y is false and A is true, in any other case is true. The symbol ≡ is the biconditional and A ≡ Y is true when both A and Y are true or when both are false.

(A ⊃ Y) is False (F)

(X ⊃ B) is True (T)

(A ≡ T) is True (T)

(B ⊃ X) is False (F)

~[(F) v ~(T)] ⋅ [~(T) v (F)]

The two negations inside the brackets must be taken into account:

~[(F) v F] ⋅ [F v (F)]

The symbol left inside the brackets v is the disjunction, and A v Y is false only  with both are false. F v (F) is False.

~[F] ⋅ [F]

Again considerating the negation:

T⋅ [F]

Finally, the symbol ⋅ is the conjunction, and A v Y is true only with both are true.

T⋅ [F] is False.

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