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natka813 [3]
2 years ago
10

Could somebody please help me understand this?!?!? (y+1)=3/5(x-3)

Mathematics
2 answers:
nirvana33 [79]2 years ago
7 0
What we wanna do is flip this equation. Assuming we are solving for x

\frac{3}{5}x  +  \frac{-9}{5} = y + 1 < Flipped

Add 9/5 to both sides!

\frac{3}{5}x +  \frac{-9}{5} +  \frac{9}{5}  = y + 1 +  \frac{9}{5}  &#10;&#10; \frac{3}{5}x = y +  \frac{14}{5}

Then we wanna divide both sides by 3/5

\frac{3}{5}x/ \frac{3}{5} = y +  \frac{14}{5}/ \frac{3}{5}&#10;&#10;x =   \frac{5y + 14}{3}
bazaltina [42]2 years ago
6 0
I hope this helps you

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3 years ago
The area of a 12-cm- wide rectangle is 180cm. what is its length?
Tcecarenko [31]

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multiply the legth times width

Step-by-step explanation:

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3 years ago
Billy is walking from the front door of his house to his bus stop, which is 960 feet away from his front door. As Billy walks ou
sasho [114]

Answer:

b) 690 - 7.5*t

c) 0 < t < 92s time (t) is independent quantity

d) 0 < s < 690ft distance from bus stop (s) is dependent quantity

e) f(0) = 690 ft away from bus stop , f(60.25) = 238.125 ft away from bus stop

Step-by-step explanation:

Part a - see diagram

part b

initial distance from bus stop s0 = 690 ft

distance covered = 7.5*t

s = s0 - distance covered

s = 690 - 7.5*t = f(t)

part c

s = 0 or s = 690

0 = 690 -7.5*t

t = 92 s

Hence domain : 0 < t < 92s time (t) is independent quantity

part d

s = 0 or s = 690

Hence range : 0 < s < 690ft distance from bus stop (s) is dependent quantity because it depends on time (t)

part e

f(0) is s @t = 0

f(0) = 690 ft away from bus stop

f(60.25) is s @t = 60.25

f(60.25) = 690 - 7.5*60.25 = 238.125 ft away from bus stop.

4 0
3 years ago
What is the equation of the line below?
Licemer1 [7]

Answer:

y = -\frac{2}{3}x + 1

Step-by-step explanation:

The equation of the line shown can be expressed in the slope-intercept formula as y = mx + b

Let's find m = slope, and b = y-intercept.

Using two points on the line, (0, 1) and (1½, 0),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 1}{\frac{3}{2} - 0} = \frac{-1}{\frac{3}{2}} = - \frac{2}{3}

y-intercept, b is where the line intercepts the y-axis = 1.

To create an equation for the line, substitute m = -⅔, b = 1 in y = mx + b.

✅The equation would be:

y = -\frac{2}{3}x + 1

4 0
2 years ago
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