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natka813 [3]
2 years ago
10

Could somebody please help me understand this?!?!? (y+1)=3/5(x-3)

Mathematics
2 answers:
nirvana33 [79]2 years ago
7 0
What we wanna do is flip this equation. Assuming we are solving for x

\frac{3}{5}x  +  \frac{-9}{5} = y + 1 < Flipped

Add 9/5 to both sides!

\frac{3}{5}x +  \frac{-9}{5} +  \frac{9}{5}  = y + 1 +  \frac{9}{5}  &#10;&#10; \frac{3}{5}x = y +  \frac{14}{5}

Then we wanna divide both sides by 3/5

\frac{3}{5}x/ \frac{3}{5} = y +  \frac{14}{5}/ \frac{3}{5}&#10;&#10;x =   \frac{5y + 14}{3}
bazaltina [42]2 years ago
6 0
I hope this helps you

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Integrala x la a treia ori ln la a doua dx va rog
Studentka2010 [4]

I don't speak Romanian, but the closest translation for this suggests you're trying to compute

\displaystyle \int x^3 \ln(x)^2 \, dx

Integrate by parts:

\displaystyle \int x^3 \ln(x)^2 \, dx = uv - \int v \, du

where

u = ln(x)²   ⇒   du = 2 ln(x)/x dx

dv = x³ dx   ⇒   v = 1/4 x⁴

\implies \displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac12 \int x^3 \ln(x) \, dx

Integrate by parts again:

\displaystyle \int x^3 \ln(x) \, dx = u'v' - \int v' du'

where

u' = ln(x)   ⇒   du' = dx/x

dv' = x³ dx   ⇒   v' = 1/4 x⁴

\implies \displaystyle \int x^3 \ln(x) \, dx = \frac14 x^4 \ln(x) - \frac14 \int x^3 \, dx

So, we have

\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac12 \left(\frac14 x^4 \ln(x) - \frac14 \int x^3 \, dx \right)

\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac18 \int x^3 \, dx

\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac18 \left(\frac14 x^4\right) + C

\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac1{32} x^4 + C

\boxed{\displaystyle \int x^3 \ln(x)^2 \, dx = \frac1{32} x^4 \left(8\ln(x)^2 - 4\ln(x) + 1\right) + C}

3 0
2 years ago
Help fast!!!
torisob [31]
Expected is -3
Expect to lose $3… bad game right there!
5 0
2 years ago
If point p partitions line BA,what would be the part to whole ratio
IRINA_888 [86]

Answer:

4 / 5

Step-by-step explanation:

From the image attached, Line BA is divided into a total of 5 equal proportions (or intervals). Point P is placed at the 4th proportion of the divided line, also the distance between point P and point A is 1 propotion. The ratio in which point P divides the line BA is given as:

Ratio = BP : PA = 4 : 1

Ratio = 4 : 1

The part to whole ratio If point p partitions line BA = BP / BA = 4 / 5

Part to whole ratio = 4/5

3 0
3 years ago
A right rectangular prism has a volume of 470.40 cm³. The length of the solid is 6.4 cm and the width is 9.8 cm.
Bogdan [553]
V = l * w * h
470.40 = 6.4 * 9.8 * h
Multiply the length and width on the right side of the equation.

470.40 = 62.72 * h
Divide both sides by 62.72
7.5 cm = h

CHECK
V = l * w * h
V = 6.4 * 9.8 * 7.5
V = 470.4 cm^3
5 0
3 years ago
Read 2 more answers
HELP ME POR FAVOR PLEASE PLEASEE
Basile [38]

Answer:

                 x=8\frac34\ \,,\quad y=8\frac12

Step-by-step explanation:

             \Delta TRS\sim \Delta LJK \quad\implies\quad \dfrac{|TR|}{|LJ|}=\dfrac{|RS|}{|JK|}=\dfrac{|ST|}{|KL|}\\\\\dfrac{4}{7}=\dfrac{5}{x}=\dfrac{6}{y+2}\\\\\\\dfrac{4}{7}=\dfrac{5}{x}\quad\implies\quad4x=5\cdot7\quad\implies\quad x=\dfrac{35}4=8\frac34\\\\\\\dfrac{5}{x}=\dfrac{6}{y+2}\quad\implies\quad 5(y+2)=6\cdot\dfrac{35}4\\\\5y+10=3\cdot\dfrac{35}2\\\\5y\ =\ \dfrac{3\cdot35}2-10\\ \div5\qquad\quad \div5\\\\y=\dfrac{3\cdot7}2-2=10\frac12-2=8\frac12

3 0
3 years ago
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