(6,2)
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Answer:
multiply the legth times width
Step-by-step explanation:
Answer:
b) 690 - 7.5*t
c) 0 < t < 92s time (t) is independent quantity
d) 0 < s < 690ft distance from bus stop (s) is dependent quantity
e) f(0) = 690 ft away from bus stop , f(60.25) = 238.125 ft away from bus stop
Step-by-step explanation:
Part a - see diagram
part b
initial distance from bus stop s0 = 690 ft
distance covered = 7.5*t
s = s0 - distance covered
s = 690 - 7.5*t = f(t)
part c
s = 0 or s = 690
0 = 690 -7.5*t
t = 92 s
Hence domain : 0 < t < 92s time (t) is independent quantity
part d
s = 0 or s = 690
Hence range : 0 < s < 690ft distance from bus stop (s) is dependent quantity because it depends on time (t)
part e
f(0) is s @t = 0
f(0) = 690 ft away from bus stop
f(60.25) is s @t = 60.25
f(60.25) = 690 - 7.5*60.25 = 238.125 ft away from bus stop.
Answer:

Step-by-step explanation:
The equation of the line shown can be expressed in the slope-intercept formula as 
Let's find m = slope, and b = y-intercept.
Using two points on the line, (0, 1) and (1½, 0),

y-intercept, b is where the line intercepts the y-axis = 1.
To create an equation for the line, substitute m = -⅔, b = 1 in
.
✅The equation would be:
