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Dvinal [7]
3 years ago
6

A student has scores of 87​, 81​, 96​, and 79 on four quizzes. What must she score on the fifth quiz to have an average of at le

ast 86​?
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
6 0

Answer:

87 points.

Step-by-step explanation:

A student has scores of 87, 81, 96, and 79 on four quizzes.

The sum of the four scores = 87 + 81 + 96 + 79 = 343

In order to have an average of atleast 86 in five quizzes, then the student must make a total of 86 × 5 = 430

Since she has a total of 343 in the four quizzes, then she must score 430 - 343 = 87  in the fifth quiz (so that she makes an average of 86 in the five quizzes).

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Answer:

The solution is given below:

Step-by-step explanation:

The computation is shown below:

= 19 +  7 divided by 2 - 5

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Therefore it is equal to the 8

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Answer:

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Step-by-step explanation:

Given

J  = (4,5)

K = (5,1)

L = (1,2)

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Required

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Start by calculating the length of the sides of the kite using:

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JK = \sqrt{(4 - 5)^2 + (5 -1)^2} = \sqrt{17}

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Hence:

LM = MJ = 3

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