How do you find the length inside a cube diagonally???
1 answer:
Solution:
We have: In the attached image, observe rectangle triangle ΔBAD
Use the Pythagorean Theorem:
BD = √(AB² + AD²)
BD = √(2² + 4²)
BD = √(4 + 16)
BD = √20
In the attached image, observe rectangle triangle ΔBDH
Use the Pythagorean Theorem:
BH = √(BD² + DH²)
BH = √(√20² + 5²)
BH = √(20 + 25)
BH = √45
BH = √(9 × 5)
BH = √9 × √ 5
BH = 3√5
BH = 3 × 2.24
BH = 6.72 cm
We have: In the attached image, observe rectangle triangle ΔBAD
Use the Pythagorean Theorem:
BD = √(AB² + AD²)
BD = √(2² + 4²)
BD = √(4 + 16)
BD = √20
In the attached image, observe rectangle triangle ΔBDH
Use the Pythagorean Theorem:
BH = √(BD² + DH²)
BH = √(√20² + 5²)
BH = √(20 + 25)
BH = √45
BH = √(9 × 5)
BH = √9 × √ 5
BH = 3√5
BH = 3 × 2.24
BH = 6.72 cm
You might be interested in
If 2 is all over then
answer is
/2
if ur question is
(13+x)^1/2=x+5
take sqrt both side
13+x=(x+5)^2
u will get
x^2+9x+12=0
solve it for x
answer is
if ur question is
(13+x)^1/2=x+5
take sqrt both side
13+x=(x+5)^2
u will get
x^2+9x+12=0
solve it for x