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muminat
3 years ago
11

Can y’all help me on question 40?!

Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

Answer:

t = 3c

Step-by-step explanation:

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Suppose that P is the point on the unit circle obtained by rotating the initial ray counterclockwise through 330 degrees. Find t
Flauer [41]

Answer:

Reference angle will be 30°

sin(330°) will be equal to \frac{-1}{2}

cos(330°) will be equal to 0.866

Step-by-step explanation:

We have given angle is 330°

As the angle 330^{\circ} is in forth quadrant

We know that in forth quadrant the reference angle is given by

Reference angle =360-angle

As the angle is 330°

So the reference angle will be =360-330=30^{\circ}

Now we have to find the value of

sin(330°) =sin(2\pi -30)=-sin(30)=\frac{-1}{2}

And now cos(330^{\circ})=cos(2\pi -30)=cos30=0.866

4 0
3 years ago
What is the equation for photosynthesis v= 1/3 bh gives the volume v of a pyramid, where b is the area of ther base and h is the
Arlecino [84]
V = 1/3 bh
3V/h = b
.........,....
3 0
3 years ago
What is the area of the irregular polygon below
garik1379 [7]

Answer:

The answer is 121.5 sq. units.

Step-by-step explanation:

To find the answer,

Area of Pentagon: About 61.5 sq. units

Area of Rectangle: 60 sq. units

61.95 + 60 = 121.5 sq. units

Thanks, I hope I got this right!

3 0
3 years ago
Read 2 more answers
The mean score on biology quiz was 62 with a standard deviation of 8, Jose’s score was a 74% what was his z score?
melisa1 [442]
(74-62)/8=3/2=1.5
Thank you hope this helps
7 0
3 years ago
Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0
Snowcat [4.5K]

Answer:

Following are the given series for all x:

Step-by-step explanation:

Given equation:

\bold{J_0(x)=\sum_{n=0}^{\infty}\frac{((-1)^{n}(x^{2n}))}{(2^{2n})(n!)^2}}\\

Let   the value a so, the value of a_n  and the value of a_(n+1)is:

\to  a_n=\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}

\to a_{(n+1)}=\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}

To calculates its series we divide the above value:

\left | \frac{a_(n+1)}{a_n}\right |= \frac{\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}}{\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}}\\\\

           = \left | \frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2} \cdot \frac {2^{2n}(n!)^2}{(-1)^2n x^{2n}} \right |

           = \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)!^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |

           = \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\

           = \frac{x^2}{2^2(n+1)^2}\longrightarrow 0   for all x

The final value of the converges series for all x.

8 0
4 years ago
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