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3 years ago

Can y’all help me on question 40?!

Mathematics

1 answer:

Anastaziya [24]3 years ago

3 0

Answer:

t = 3c

Step-by-step explanation:

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Suppose that P is the point on the unit circle obtained by rotating the initial ray counterclockwise through 330 degrees. Find t

Flauer [41]

Answer:

Reference angle will be 30°

sin(330°) will be equal to $\frac{-1}{2}$

cos(330°) will be equal to 0.866

Step-by-step explanation:

We have given angle is 330°

As the angle $330^{\circ}$ is in forth quadrant

We know that in forth quadrant the reference angle is given by

Reference angle $=360-angle$

As the angle is 330°

So the reference angle will be $=360-330=30^{\circ}$

Now we have to find the value of

sin(330°) $=sin(2\pi -30)=-sin(30)=\frac{-1}{2}$

And now $cos(330^{\circ})=cos(2\pi -30)=cos30=0.866$

4 0

3 years ago

What is the equation for photosynthesis v= 1/3 bh gives the volume v of a pyramid, where b is the area of ther base and h is the

Arlecino [84]

V = 1/3 bh
3V/h = b
.........,....

3 0

3 years ago

What is the area of the irregular polygon below

garik1379 [7]

Answer:

The answer is 121.5 sq. units.

Step-by-step explanation:

To find the answer,

Area of Pentagon: About 61.5 sq. units

Area of Rectangle: 60 sq. units

61.95 + 60 = 121.5 sq. units

Thanks, I hope I got this right!

3 0

3 years ago

Read 2 more answers

The mean score on biology quiz was 62 with a standard deviation of 8, Jose’s score was a 74% what was his z score?

melisa1 [442]

(74-62)/8=3/2=1.5
Thank you hope this helps

7 0

3 years ago

Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0

Snowcat [4.5K]

Answer:

Following are the given series for all x:

Step-by-step explanation:

Given equation:

$\bold{J_0(x)=\sum_{n=0}^{\infty}\frac{((-1)^{n}(x^{2n}))}{(2^{2n})(n!)^2}}\\$

Let the value a so, the value of $a_n$ and the value of $a_(n+1)$ is:

$\to a_n=\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}$

$\to a_{(n+1)}=\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}$

To calculates its series we divide the above value:

$\left | \frac{a_(n+1)}{a_n}\right |= \frac{\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}}{\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}}\\\\$

$= \left | \frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2} \cdot \frac {2^{2n}(n!)^2}{(-1)^2n x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)!^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\$

$= \frac{x^2}{2^2(n+1)^2}\longrightarrow 0$ for all x

The final value of the converges series for all x.

8 0

4 years ago