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Yuliya22 [10]
3 years ago
8

Can someone plz help me with these problems!!!

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0
Yes I can if you still need help
tensa zangetsu [6.8K]3 years ago
6 0

I believe you spelled "Caramel" wrong.

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You are going to the amusement park with some friends! There are 3 different rides you all want to get to before the park closes
spin [16.1K]

Answer:

The second one

Step-by-step explanation:

4 0
2 years ago
Solve the equation<br> —3x +1+ 10x = x +4 <br> X=1/2<br> X=5/6 <br> X=12<br> X=18
iren [92.7K]

Answer:

x = 1/2

Step-by-step explanation:

-3x + 1 + 10x = x + 4

7x + 1 = x + 4

6x + 1 = 4

6x = 3

x = 3/6

x = 1/2

4 0
3 years ago
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In a wood there are 420 silver birch trees 160 oak trees and 300 wild cherry trees what percentage is the oak trees give answer
frosja888 [35]
That would be 7.2 if my calculations are correct
6 0
3 years ago
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Deanna and Alise are shopping. Deanna buys a sweater for $25 and 3 tubes of lip gloss. Alise buys a hat for $13 and five tubes o
geniusboy [140]

Answer:

$1.5

Step-by-step explanation:

So you need to subtract 25 from 13 = 12 then take 3 and 5 and add = 8 then you need to divide 12 from 8 = 1.5 so i do believe that the tubes are $1.5

I may be wrong and im sorry but pls try :3

3 0
2 years ago
Complete the squar3
cricket20 [7]

9514 1404 393

Answer:

  1. 4
  2. -2
  3. 4
  4. 2
  5. -2±√2

Step-by-step explanation:

In order to fill the first blank, we need to look at the second line to see what the coefficient of x is.

  1. x² +<u> </u><u>4 </u>x +2 = 0

The constant is subtracted from both sides to get the second line.

  2. x² +4x = <u> -2 </u>

The value that is added on the third line is the square of half the x-coefficient: (4/2)² = 4

  3. x² +4x +<u> 4 </u> = -2 +4

On the fourth line, the left side is written as a square, and the right side is simplified. The square root is taken of both sides.

  4. √(x +2)² = ±√<u> 2 </u>

Finally, 2 is subtracted from both sides to find the values of x.

  5. x = <u> -2 ±√2 </u>

8 0
2 years ago
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