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vodomira [7]
3 years ago
14

HELP ASAP!!! please i know its Friday but i need help with home work

Mathematics
2 answers:
mote1985 [20]3 years ago
8 0
The answer is one solution
Anika [276]3 years ago
6 0
The answer is the second one. It only has one solution
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If u(x)=-2x^2+3 and v(x)=1/x what is the range of (u*v)(x) **the picture should help
nasty-shy [4]
We have that
u(x)=-2 x^{2} +3 \\ \\ v(x)= \frac{1}{x}
u(v(x))=u( \frac{1}{x})=-2( \frac{1}{x} )^{2}  +3 \\ u( \frac{1}{x})= \frac{(3 x^{2} -2)}{ x^{2} }

using a graph tool
see the attached figure

The horizontal asymptote of this function is at <span>y=3</span><span>.
So,
the range of this function is from </span><span>(−∞,3<span>)</span></span>

5 0
3 years ago
Read 2 more answers
I shared 3 cars with my cousins I have 5 cousins and me. I want to know how many people will be in each car
tatuchka [14]

there will be 2 people in each car

5 0
3 years ago
HELP ASAP!!! 40 POINTS
ICE Princess25 [194]

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:

(-15,-10).

<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>

It is given by the derivative at x = x0, that is:

m = f^{\prime}(x_0).

In this problem, the function is:

f(x) = 0.2x^2 + 5x - 12

Hence the derivative is:

f^{\prime}(x) = 0.4x + 5

For a slope of -1, we have that:

0.4x + 5 = -1

0.4x = -6

x = -15.

For a slope of 1, we have that:

0.4x + 5 = 1.

0.4x = -4

x = -10

Hence the interval is:

(-15,-10).

More can be learned about derivatives and tangent lines at brainly.com/question/8174665

#SPJ1

8 0
2 years ago
I’m too lazy to do it so if someone can do it it would mean a lot
Dafna11 [192]

Answer:

a

Step-by-step explanation:

did the math :)

brainliest pls!

5 0
3 years ago
Read 2 more answers
Please help, it's urgent!
Aneli [31]

For this case we have to, by defining properties of powers and roots the following is fulfilled:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

We must rewrite the following expression:

\sqrt [3] {8 ^ {\frac {1} {4} x}}

Applying the property listed we have:

\sqrt [3] {8 ^ {\frac {1} {4} x}} = 8 ^ {\frac{\frac {1} {4} x} {3} }= 8 ^ {\frac {1} {4 * 3} x} = 8 ^ {\frac {1} {12} x}

Using the property again we have to:

8 ^ {\frac {1} {12} x} = \sqrt [12] {8 ^ x}

Thus, the correct option is option C

Answer:

Option C

6 0
4 years ago
Read 2 more answers
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