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NemiM [27]
2 years ago
7

Carol has 7 rolls of pennies containing 50 coins each, 11 rolls of nickels containing 40 coins each, 3 rolls of dimes containing

50 coins each, and 12 rolls of quarters containing 40 coins each. How much money does she have?
Mathematics
1 answer:
saveliy_v [14]2 years ago
8 0

Answer: Carol has $160.50

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The inequality that shows the maximum number of dresses she can buy is $7.15p+$9.95=$60 the maximum # of dresses she can buy is 7
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3 years ago
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#13. 6x — Зу = 8
Ne4ueva [31]

#13

  • 6x — Зу = 8
  • 3y = 6x - 8
  • y = 6/3x - 8/3
  • y = 2x - 8/3
  • The slope = 2
  • The y- intercept = - 8/3

#14

  • 7x = 5y + 2
  • 5y = 7x - 2
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#15

  • - 6у + 4х = 8
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#16 is not clear

8 0
2 years ago
5. 5 sec2 0 = 6 sec o
bija089 [108]

Answer:

11.5 sec

Step-by-step explanation:5.5+6=11.5

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3 years ago
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alex purchased 20,000 for a new car. The cars value depreciates 7.25% each year. What will be the value of the car five years af
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The answer would be 18550$. you would find 7.25% of 20000, multiply it by 5, then subtract it from 20000 to get 18550$.
8 0
3 years ago
Do one of the​ following, as appropriate.​ (a) Find the critical value z Subscript alpha divided by 2​, ​(b) find the critical v
aliya0001 [1]

Answer:

t=\pm 2.95

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

Data given

Confidence =0.99 or 99%

\alpha=1-0.99=0.01 represent the significance level

n =16 represent the sample size

We don't know the population deviation \sigma

Solution for the problem

For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:

df=n-1=16-1=15

We know that \alpha=0.01 so then \alpha/2=0.005 and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:

"=T.INV(0.005;15)" and we got t_{\alpha/2}=-2.95 on this case since the distribution is symmetric we know that the other critical value is t_{\alpha/2}=2.95

8 0
3 years ago
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