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NemiM [27]
3 years ago
7

Carol has 7 rolls of pennies containing 50 coins each, 11 rolls of nickels containing 40 coins each, 3 rolls of dimes containing

50 coins each, and 12 rolls of quarters containing 40 coins each. How much money does she have?
Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer: Carol has $160.50

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The front wall of the storage shed is in the shape of a trapezoid.
KonstantinChe [14]

Answer:

66 square feet

Step-by-step explanation:

please review the attachment for a detailed explanation

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How do you solve 2x + 1= 3x - 3
Alex Ar [27]
X = 4 is the answer lol
6 0
3 years ago
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Refer previous problem. Suppose that you wish to estimate the difference between the mean acidity for rainfalls at two different
aivan3 [116]

Answer:

Hence,we need at least 136 rainfall PH values in the sample i.e

n ≥ 136

Step-by-step explanation:

We are given that:

(σ1)^2 = (σ2)^2 = Population variance = 0.25

So, E < 0.1

Confidence coefficient (c) = 0.9

n = n1 = n2

For confidence level, 1 - α = 0.9,we'll determine Z (α /2) = Z 0.05 by looking up 0.005 using the normal probability table which i have attached.

So, Z (α /2) = 1.645

The margin of error E is given as;

E = Z (α /2)√[(σ1)^2)/n1] + [(σ2)^2)/n2]

= Z (α /2)√({(σ1)^2 + (σ2)^2}/n) < 0.1

Multiply both sides by √n to get;

Z (α /2)√(σ1)^2 + (σ2)^2} < 0.1√n

Divide both sides by 0.1;

{Z (α /2)√(σ1)^2 + (σ2)^2}}/0.1 <√n

When we square each side, we get

{Z (α /2)√(σ1)^2 + (σ2)^2}}/0.1} ^2 < n

We'll now fill in the known values and solve;

n > ( 1.645 x √{(0.25 + 0.25)/0.1}^2

n > 135.3 or approximately n > 136

Hence,we need at least 136 observations in the sample i.e

n ≥ 136

7 0
3 years ago
Pencils come in packages of 10.Erasers come in packages of 12. Phillips wants to purpose the smallest number of pencils and eras
balandron [24]

Answer:

The answer to your question is:

Packages of pencils = 6

Packages of erasers = 5

Step-by-step explanation:

Data

Pencils = 10/package

Erasers = 12 / package

Process

Find the least common factor of 10 and 12

                                    10     12     2

                                     5       6     2

                                     5       3     3

                                     5        1    5

                                      1

LCF = 2 x 2 x 3 x 5 = 60

Finally divide 60 by the number of pencils or erasers in each package

Packages of pencils = 60/10 = 6

Packages of erasers = 60/12 = 5

                                                 

5 0
3 years ago
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