Question

A balloon is filled with He gas at sea level and at constant temperature raised to an altitude where the pressure is 2/3 atm. If the initial volume of balloon is 10. L,
what is the balloon's change in volume?

Answer 1

Answer: The balloon's change in volume is 5 L

Explanation:

To calculate the change in volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure of gas (at sea level) = 1 atm

$V_1$ =  initial volume of gas = 10 L

$P_2$ = final pressure of gas= $\frac{2}{3}atm$

$V_2$ = final volume of gas = ?

Putting values in above equation, we get:

$1\times 10=\frac{2}{3}\times V_2$

$V_2=\frac{30}{2}=15L$

The final volume of the ballon is 15 L

Thus the change in volume is (15-10)L = 5L