What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?
1 answer:
<h2>Hello!</h2>
The answer is:
The third option, 79.8%
<h2>Why?</h2>To calculate the percent yield we need to divide the actual yield by the theoretical yield, and then, multiply it by 100 in order to find the percent.
So, we from the statement we know the following information:
Let's use the following formula and substitute the given information:
Hence, we have that the correct option is the third option, the percent yield is 79.8%.
Have a nice day!
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Answer:
b)15.0°C
Explanation:
Specific Heat of Water=4.2 J/g°C
This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.
∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.
80×4.2 J=336 J
Total Energy Provided=1680 J
The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}
Temperature increase=
=5°C
Initial Temperature =10°C
Final Temperature=Initial + Increase in Temperature
=10+5=15°C