In HCl-HCl, the hydrogen-chlorine link is a polar covalent bond. It is produced when two atoms share an electron pair.
When atoms with various electronegativities share electrons in a covalent link, the result is a polar covalent bond. Think about the molecule of hydrogen chloride (HCl). In order to generate an inert gas electron configuration, each atom of HCl needs an additional electron. Despite having a stronger electronegativity than hydrogen, the chlorine atom cannot remove an electron from hydrogen due to its inability to attract electrons. As a result, a polar covalent bond in hydrogen chloride has an unbalanced distribution of bonding electrons.
Learn more about electronegativity here-
brainly.com/question/17762711
#SPJ4
Answer:
Is this from edge?
if so which lesson is it from and is this an assignment or a quiz?
I think the answer is C (Much of the evidence for evolution comes from fossils.)
Answer:
energy required is 0.247kJ
Explanation:
The formula to use is Energy = nRdT;
Where n is number of mole
R is the molar gas constant
dT is the change in temperature
n = reacting mass of mercury / molar mass of mercury = 27.4/200.59 = 0.137
dT = final temperature - initial temperature = 376.20 - 158.30 = 217.90K
R = 8.314Jper mol per Kelvin
Energy = 0.137 x 8.314 x 217.90 = 247.12J
Energy in kJ= 247.12/1000= 0.247kJ
When you oxidize something you are removing electrons
When you reduce something you're adding electrons
So the one that is gaining electrons is oxidizing the other substance by taking away relectrons from it and the one losing electrons is reducing the other substance by adding electrons to it.
You can figure out which is which by looking at the charge of each substance
Mg has a charge of 2+ because it had 2 electrons in its outer shell which it will lose to have a full outer shell.
I has a charge of -1 because it has 7 electrons in its outer shell and it gains 1 to have a full outer shell.
Mg is giving electrons to I so it's reducing it and is the reducing agent
I is taking electrons from Mg so it's oxidizing it and is the oxidizing agent.