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artcher [175]
3 years ago
9

What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?

Chemistry
1 answer:
BaLLatris [955]3 years ago
7 0
<h2>Hello!</h2>

The answer is:

The third option, 79.8%

<h2>Why?</h2>

To calculate the percent yield we need to divide the actual yield by the theoretical yield, and then, multiply it by 100 in order to find the percent.

So, we from the statement we know the following information:

ActualYield=220.0g\\TheoreticalYield=275.6g

Let's use the following formula and substitute the given information:

PercentYield=\frac{ActualYield}{Theoretical}*100\\\\

PercentYield=\frac{220g}{275.6g}*100=0.798*100=79.8(percent)

Hence, we have that the correct option is the third option, the percent yield is 79.8%.

Have a nice day!

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Answer: The excess amount changes from a gas into a liquid or solid (ice). The process of water changing from a gas to a liquid is called "condensation," and when gas changes directly into a solid, it is called "deposition." These two processes are how clouds form.

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Given the equation representing a reversible reaction:
tester [92]

Answer:

- Acetic acid (CH₃COOH) and hydronium ion (H₃O⁺)

Explanation:

Hello,

In this case, based on the acid-base theory which states that acids are known as H⁺ donors, if we consider the direct reaction:

CH_3COOH(aq) + H_2O \rightarrow CH_3COO^-(aq) + H_3O^+(aq)

It is clear that the acetic acid is the first H⁺ donor as it losses one H⁺ to turn into the acetate ion. Moreover, if we consider the inverse reaction:

CH_3COO^-(aq) + H_3O^+(aq)\rightarrow CH_3COOH(aq) + H_2O

It is also clear that the hydronium ion is the second H⁺ donor as it losses one H⁺ to turn into water.

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When driving a truck,is fuel crucial?
Natali [406]

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The answer is yes.

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An endothermic reaction has
pav-90 [236]
Sorry I don’t know the answer but sorry about this person
5 0
3 years ago
Read 2 more answers
Predict the charge on the monatomic ions formed from the following atoms in binary ionic compounds:(a) |(b) Sr(c) K(d) N(e) S(f)
Pavel [41]

Answer:

(a) I⁻ (charge 1-)

(b) Sr²⁺ (charge 2+)

(c) K⁺ (charge 1+)

(d) N³⁻ (charge 3-)

(e) S²⁻ (charge 2-)

(f) In³⁺ (charge 3+)

Explanation:

To predict the charge on a monoatomic ion we need to consider the octet rule: atoms will gain, lose or share electrons to complete their valence shell with 8 electrons.

(a) |

I has 7 valence electrons so it gains 1 electron to form I⁻ (charge 1-).

(b) Sr

Sr has 2 valence electrons so it loses 2 electrons to form Sr²⁺ (charge 2+).

(c) K

K has 1 valence electron so it loses 1 electron to form K⁺ (charge 1+).

(d) N

N has 5 valence electrons so it gains 3 electrons to form N³⁻ (charge 3-).

(e) S

S has 6 valence electrons so it gains 2 electrons to form S²⁻ (charge 2-).

(f) In

In has 3 valence electrons so it loses 3 electrons to form In³⁺ (charge 3+).

3 0
3 years ago
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