Solve using a system of equations. Tickets to a local movie were sold at $6.00 for adults and $4.50 for students. If 110 tickets
1 answer:
Answer:
The number of adults tickets is 80 and the number of students tickets is 30
Step-by-step explanation:
Given as :
The tickets price for adults = $6.00
The tickets price for students = $4.50
Total number tickets were sold = 110
Total Price of 110 tickets = $615.00
Now,
Let The number of adults tickets sold = A
The number of students tickets sold = S
So, according to question
A + S = 110
And 6 A + 4.5 S = 615
Or, 6 A + 6 S = 660 .....1
6 A + 4.5 S = 615 ......2
Solving the equations
( 6 A + 6 S ) - ( 6 A + 4.5 S ) = 660 - 615
Or, ( 6 A - 6 A ) ( 6 S - 4.5 S ) = 45
or, ( 6 S - 4.5 S ) = 45
or, 1.5 S = 45
∴ S =
I,e S = 30
Put the value of S in eq 1
So, 6 A + 6 × 30 = 660
Or, 6 A = 660 - 180
Or 6 A = 480
∴ A =
I.e A = 80
Hence The number of adults tickets is 80 and the number of students tickets is 30 . Answer
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Step-by-step explanation:
1. You have the following information of Plan A:
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- A 4 minutes call costs $1.08.
2. For Plan B, you know that the cost of is given by the equation:
3. Therefore, you can compare both plans by finding the cost of a call of 2 minutes and a call of 4 minutes of Plan B. You can calculate this by giving these values to :
4. Substitute the values into the equation:
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5. Therefore, Plan A is cheaper, because the cost of a 2-minute call and a 4-minute call is less than the cost of a 2-minute call and a 4-minute of Plan B call.