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SSSSS [86.1K]
3 years ago
13

What is solution set for the quadratic equation ×^2 + 10×+25=0​

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

x=-5

Step-by-step explanation:

x squared+10x+25 factors into (x+5)(x+5). Set x equal to 0 and you get x=-5. To check, plug in negative 5 and you get 25+ -50 + 25=0 which is true.

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Which of the following could NOT be the lengths of the sides of a triangle?
Furkat [3]

Given:

Sides of triangles in the options.

To find:

Which could NOT be the lengths of the sides of a triangle.

Solution:

Condition for triangle:

Sum of two smaller sides of a triangle must be greater than the longest side.

In option A,

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Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.

In option B,

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Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.

In option C,

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Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.

In option D,

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Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.

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8 0
3 years ago
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ELEN [110]

Answer:

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Step-by-step explanation:

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Now, we are asked that for how long from the launch does the projectile stays in the air.

Therefore, we have to solve the equation (1) making f(x) as zero.

Hence, 10x(x - 4) = 0

⇒ x = 0 or x = 4

(As x can not be zero since at x = 0 sec, the projectile was at the ground.}

Hence, x = 4 seconds.

Therefore, the projectile was in the air for 4 seconds. (Answer)

4 0
3 years ago
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luda_lava [24]

Answer:

1/8

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olga55 [171]

Answer:

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Step-by-step explanation:

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3 years ago
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