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3 years ago

Solve for n: 21k – 3n + 9p > 3p + 12.

2 answers:

3 0

Solve for n.

21k−3n+9p>3p+12

Add -21k to both sides.

21k−3n+9p+−21k>3p+12+−21k

−3n+9p>−21k+3p+12

Add -9p to both sides.

−3n+9p+−9p>−21k+3p+12+−9p

−3n>−21k−6p+12

Divide both sides by -3.

−3n/−3 > −21k−6p+12/−3

n < 7k+2p−4

$\huge{\boxed{\boxed{\boxed{\boxed{\hbox{So your answer is B.}}}}}}$

Thepotemich [5.8K]3 years ago

3 0

solve for n.21k−3n+9p>3p+12Add -21k to both sides.21k−3n+9p+−21k>3p+12+−21k−3n+9p>−21k+3p+12Add -9p to both sides.−3n+9p+−9p>−21k+3p+12+−9p−3n>−21k−6p+12Divide both sides by -3.−3n/−3 > −21k−6p+12/−3n < 7k+2p−4

ANSWER IS B

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<u>Solut</u><u>ion</u><u>:</u><u>-</u><u>1</u><u>0</u>

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<h3>Further explanation</h3>

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