y = x^2 + 2x...eqn 1
y = 3x + 20...eqn 2
subst for y in eqn 1...
=> x^2 +2x = 3x +20
=> x^2 - x - 20 =0
=> (x-5) (x+4) =0
=> x = 5 or -4
for x =5, y = 35 (sub for x in eqn 1 or 2)
for x = -4, y = 8 (sub for x in eqn 1 or 2)
This is hard to solve when we don't know the visual graph this question is trying to refer from
Answer:
435.2kg (1DP)
Step-by-step explanation:
0.64x680
64 divided by 100 = 0.64
Answer:
Because we don't know the exact shape of the population distribution since they are not Normally distributed and they are also not very non-Normal
Step-by-step explanation:
We are given;
Population standard deviation;μ = 200
Population standard deviation; σ = 35
Sample size; n = 30
We are told that the weights are not Normally distributed and they are also not very non-Normal. Therefore it means we don't know the exact shape of the population distribution and as such we can't calculate the probability that a randomly selected passenger weighs more than 200 pounds.
Answer:
So, the odds that a taxpayer would be audited 28 to 972 or 2.88%
Step-by-step explanation:
Given
Let P(A) = Probability of irs auditing
P(A) = 2.8%
Let n = number of those who earn above 100,000
To get the odds that taxpayer would be audited, we need to first calculated the proportion of those that will be audited and those that won't.
If the probability is 2.8% then 2.8 out of 100 will be audited. That doesn't make a lot of sense since you can't have 2.8 people; we multiply the by 10/10
i.e.
Proportion, P = 2.8/100 * 10/10
P = 28/1000
The proportion of those that would not be audited is calculated as follows;
Q = 1000 - P
By substituton
Q = 1000 - 28
Q = 972
So, the odds that a taxpayer would be audited 28 to 972 or P/Q
P/Q = 28/972
= 0.0288065844
= 2.88% --- Approximately
