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3 years ago

8

Solve the system of equations. – 5x + 2y = 9 y = 7x X = Y =

2 answers:

Helen [10]3 years ago

6 0

Answer:

x = 1

y = 7

Step-by-step explanation:

Your system of equations is

-5x + 2y = 9

y = 7x

The easiest way to solve this is by substitution. This means that you set one of the equations equal to a variable and you plug that variable into the variable of the other equation. The second equation (y = 7x) is already set up this way so we will plug it into the first equation.

-5x + 2(7x) = 9

-5x + 14x = 9

9x = 9

(9x)/9 = (9)/9

x = 1

You have found x. Now, plug this number into the second equation (y = 7x) to find the value of y.

y = 7(1)

y = 7

Sphinxa [80]3 years ago

5 0

Answer:

<em> x−y = 9 , x + y = 6</em>

<em>x + y = 4 , x − y = 2</em>

<em>x + 2 y = 4 , x − y = − 3 </em>

<em>try out these examples?</em>

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Step-by-step explanation:

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FrozenT [24]

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Step-by-step explanation:

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andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
$\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}$

where:

The divisor = 2x -3

Using the long division method, we have:

$\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}$

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

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