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My name is Ann [436]
3 years ago
8

The diameter of a human red blood cell is 0.000009 m. The diameter of a cold virus is 0.00000003 m Approximately how many times

as large is the diameter of a red blood cell as the diameter of a cold virus? A :3⋅10^-14 B:3⋅10 ^−2 C :3⋅10 ^1 D ;3⋅10 ^2
Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

D. 3*10^2

Step-by-step explanation:

Given the diameter of human red blood cell =  0.000009 m

diameter of a cold virus = 0.00000003 m

To know how many times as large is the diameter of a red blood cell as the diameter of a cold virus, we will take the ratio of the diameter of human red blood cell to that of a cold virus as shown;

diameter of human red blood cell/diameter of a cold virus = 0.000009 m/0.00000003 m

= 9*10^-6/3*10^-8

= 9/3 * 10^-6-(-8)

= 3 * 10^(-6+8)

= 3*10^2

Hence the diameter of a red blood cell is 3*10^2 larger than that of the cold virus

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\angle1\cong\angle2 corresponding angles, therefore

m∠1 = m∠2 → m∠2 = 130°

\angle2\cong\angle3 vertical angles, therefore

m∠2 = m∠3 → m∠3 = 130°


If ∠1 and ∠2 are complementary, then m∠1 + m∠2 = 90°.

If ∠2 and ∠3 are complementary, then m∠2 + m∠3 = 90°

Therfore

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B.



Let's simply look at each conjecture and determine if it's true or false.



A. 2n– 1 is odd if n is positive: Since n is an integer, 2n will always be even. And an even number minus 1 is always odd. Doesn't matter if n is positive or not. So this conjecture is true.



B. 2n– 1 is always even: Once again, 2n will always be even. So 2n-1 will always be odd. This conjecture is false.



C. 2n– 1 is odd if n is even: 2n is always even, so 2n-1 will always be odd, regardless of what n is. So this conjecture is true.



D. 2n– 1 is always odd: 2n will always be even. So 2n-1 will always be odd. Once again, this conjecture is true.



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Step-by-step explanation:

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