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tensa zangetsu [6.8K]
3 years ago
8

Morgan made a mistake when subtracting the rational expressions below.

Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer : D

\frac{3t^2-4t+1}{t+3} - \frac{t^2+2t+2}{t+3}

The denominators are  same

So we combine the numerators

\frac{(3t^2-4t+1)-(t^2+2t+2)}{t+3}

To remove parenthesis we distribute negative sign inside the second parenthesis

\frac{3t^2-4t+1-t^2-2t-2)}{t+3}

\frac{3t^2-4t+1-t^2-2t-2)}{t+3}

\frac{2t^2-6t-1)}{t+3}

Morgan made a mistake. He forgot to distribute the negative sign

Morgan forgot to distribute the negative sign to two of the terms 2t  and 2 inside second parenthesis

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The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

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Then, the mean of the distribution of sample mean is given by,

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<em>n</em> = 50.

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Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

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*Use a <em>z</em>-table for the probability.

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3.19x10^8 /8.23x10^5<br><br> Please show work
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