X = 37 degrees.
Sine and cosine are complementary, which means when they are added together, the equal 90. So, to find sine, subtract 53 from 90, to get x = 37.
Here is an image to show this.
I hope this helps!
Answer:
A
Step-by-step explanation:
Automatically if you use the intercept (where it cuts the line) which would be 3.
Answer: The graph in the bottom right-hand corner
(see figure 4 in the attached images below)
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Explanation:
Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.
Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.
After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.
Answer:
that I have a panda but the black on it and I have a ok that you can come over for a few days to come back and I was in work today and it is a very long day at the end with the kids to school tomorrow right ha I have a panda but the black one of the day I can get some
over the place
What is the question ill try to help