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katovenus [111]
3 years ago
10

There are 18 men on 2 baseball teams. 2/3 of them brought their sons to watch them play. How many brought their son?

Mathematics
1 answer:
Rudik [331]3 years ago
6 0
12

reasoning:

2/3 of 18 is 12
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The local newspaper has letters to the editor from 20 people. If this number represents 8​% of all of the​ newspaper's readers,
zlopas [31]

let the all readers be x

8%=20×100%÷x

8%x=2000%

x=2000%÷8%

x=250

3 0
3 years ago
8 + 5[(5 + 3)2 - (32 + 2)]
jeka57 [31]

Add: 5 + 3 = 8

Exponentiation: the result of step No. 1 ^ 2 = 8 ^ 2 = 64

Add: 32 + 2 = 34

Subtract: the result of step No. 2 - the result of step No. 3 = 64 - 34 = 30

Multiple: 5 * the result of step No. 4 = 5 * 30 = 150

Add: 8 + the result of step No. 5 = 8 + 150 = 158

plz mark me as brainliest :)

3 0
3 years ago
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Is rolling doubles a simple event or compound event? Explain.<br><br><br> (rolling double dice)
nexus9112 [7]
You have to consider the sample space. In this example the sample space

is {1,2,3,4,5,6}

A simple event can be defined as a SINGLE outcome : Example getting a 3 OR 5 OR any other number from the sample space.

Now if you roll 1 dice & you want to get an even number (2,4,6) then you have chosen from the sample space 3 outcome & this is a compound event

Equally if you roll 2 dice and want to get "one" and/or "three" this is a compound event since you have chosen 2 outcome from the sample space.

Mind you, if you want 5 And 5 when rolling two dice it's a simple event because you have chosen ONE outcome from the sample space.

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4 0
3 years ago
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Describe a real world problem you could solve with the help of a yardstick and a calculator.
jekas [21]
There are many options, let me tell you three
- how many square feet is your house
- <span>how tall you are in centimeters. use the yardstick to measure yourself then calculate it into centimeters
- </span>needing to find the area of a space in order to purchase a couch you need the yardstick
I hope these options are useful
4 0
3 years ago
Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to
mezya [45]

Answer:

The confidence interval is (24116.3878,24883.6122).

Step-by-step explanation:

We are given the following information in the question:

Population mean, \mu = $23,500

Sample mean,\bar{x} = $24,500

Sample standard deviation,s = $2,800

Sample size, n =  146

Confidence interval:

\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}  

Putting the values, we get,

t_{critical}\text{ at}~\alpha_{0.05} = \pm 1.655436

24500 \pm 1.65543(\frac{2800}{\sqrt{146}} ) = 24500 \pm 383.6122 = (24116.3878,24883.6122)

The confidence interval is (24116.3878,24883.6122).

5 0
3 years ago
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