Answer:
Confidence limit = [52.8%, 75.2%]
Step-by-step explanation:
± 
where the value will be taken from the z-table for 95% confidence interval
1-0.95= 0.05/2= 0.025
0.95+0.025= 0.0975
From the z-table the value of corresponding to 0.0975 is 1.96
± 
± 
± 
% ± 
%
so the confidence interval is
%
%
![[52.8, 75.2]](https://tex.z-dn.net/?f=%5B52.8%2C%2075.2%5D)
Substitute 15 for p and 12 for q in p + q. We get 15 + 12, or 27.
The answer is 7 sections
In this type of question, you just need to divide the total length of the line that drawn by Jason with the length of sections that Jason want.
So, the calculation would be:
(7/8) / (1/8)
= 7/8 x 8/1
= 7 amount of sections
Answer:
That's true because they can be different numbers but they are both even.
Answer:
The probability that a student earns a grade of A is 1/7.
Let E be an event and S be the sample space. The probability of E, denoted by P(E) could be computed as:
P(E) = n(E) / n(S)
As the total number of students = n(S) = 35
Students getting the grade A = n(E) = 5
So, the probability that a student earns a grade of A:
P(E) = n(E) / n(S)
= 5/35
= 1/7
Hence, the probability that a student earns a grade of A is 1/7.
Keywords: probability, sample space, event
