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emmainna [20.7K]
3 years ago
9

Solve the equation you chose. Then check to see if the solution is reasonable Choose an equation. A. 5h - 12 = 27 B. 5h + 12 = 2

7​
Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

muynayo

Step-by-step explanation:

Julli [10]3 years ago
4 0

Answer:

A. h=39/5,  B. h=3

Step-by-step explanation:

5h-12=27.                          5h+12=27

5h=27+12.                         5h=27-12

5h=39                               5h=15

h=39/5.                             h=3

5(39/5)-12=27                   5(3)+12=27

39-12=27                           15+12=27

27=27                                27=27

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Answer:

Step-by-step explanation:

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3 years ago
Write a polynomial f(x) that satisfies the given conditions.
patriot [66]

Answer:

f(x) = (x-4)(x-\frac{1}{2})^2 = x^3-5x^2+4.25x -1

Step-by-step explanation:

Recall, if we have a polynomial of the form (x-a)^k \cdot (x-b)^m, then we say that a is a zero of multiplicity k and b is a zero of multiplicty m. For example, in the polynomial of the form (x+5)^10(x-2)^3 -5 is a zero of multiplicity 10 and 2 is a zero of multiplicity 3. If we want to know the degree of the polynomial,  just add the multiplicity of both zeros (13 in our example).

In this case, we know that the degree of our polynomial should be at least 3(multiplicity 2 and multiplicity 1). So, lets take the polynomial of the form

f(x)=(x-a)(x-b)^2).

In here, a is a zero with multiplicity 1 and b is a zero with multiplicity 2. We are also given that

f(0) = -1 = (0-a)(0-b)^2 = -a\codt b^2.

Which implies that 1 = a\cdot b^2. Since the square of any number is a positive number, it must happen that a>0. So, we have that

b= \pm \sqrt[]{\frac{1}{a}}.

We can choose any value of a and solve for b. Let us choose a=4. So we can have b=1/2 or b=-1/2. Let's use b=1/2. So our polynomial would be

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6 0
4 years ago
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solniwko [45]
<h3>Answer:  $7.99</h3>

Explanation:

Pick any point listed and divide the y coordinate over the x coordinate.

The simplest choice is the point where x = 1

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Or we could say something like

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3 0
3 years ago
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