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3 years ago

ABCD is a rhombus. = 5.5 cm and = 4 cm. What is the area of the rhombus?

Mathematics

2 answers:

Dimas [21]3 years ago

5 0

Answer:

The correct answer is option A, $11 cm^2$

Step-by-step explanation:

Area of Rhombus

$= (Diagonal 1 x Diagonal 2)/2\\$

Substituting the given values in above equation we get -

$= (5.5 cm * 4 cm )/2\\= 22 cm^2 /2\\= 11 cm^2$

Angelina_Jolie [31]3 years ago

3 0

The formula for solving a rhombus is A = P*Q/2

5.5×4 =22

22÷2 = 11

Awnswer: 11 cm²

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Ket [755]

The area of the house is the amount of space on the house.

The length of the addition is x + 20
The area of the original house is $x^2 + 30x + 200$

<h3>The length of the addition</h3>

The area of the addition is given as:

$Area = x^2 + 10x - 200$

Expand

$Area = x^2 + 20x - 10x - 200$

Factorize

$Area = x(x + 20) - 10(x + 20)$

Factor out x + 20

$Area = (x -10)(x + 20)$

The width of the addition is x - 10.

Hence, the length of the addition is x + 20

<h3>The area of the original house</h3>

The dimension of the original house is

x + 20 by x + 10

So, the area is:

$Area =(x + 20)(x + 10)$

Expand

$Area =x^2 + 20x + 10x + 200$

This gives

$Area =x^2 + 30x + 200$

Hence, the area of the original house is $x^2 + 30x + 200$

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8 0

2 years ago

Plz Help...................

joja [24]

Answer:

55.5 u^2

Step-by-step explanation:

Split the quadrilateral into 2 triangles. There are two ways to do this, but I'm only doing one of them.

On the 5-11 triangle, use the two of the lengths and plug them into the triangle area formula. (L x W)/2 = A

5-11 triangle area: 27.5

Do the same for the 7-8 triangle. Plug it into the same formula.

7-8 triangle area: 28

Add the two areas. 27.5 + 28 = 55.5

8 0

3 years ago

Can I have help and pls don't answer if you don't know

sergij07 [2.7K]

Answer:

I think its A

Step-by-step explanation:

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3 years ago