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ruslelena [56]
3 years ago
11

Divide 49p in the ratio of 4:2:1

Mathematics
1 answer:
frozen [14]3 years ago
7 0

4+2+1=7

49p/7=7p

4units:2units:1unit

4 times 7p=28p

2 times 7p=14p

1 times 7p=7p

divided it is

28p:14p:7p

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The town of lantana needs $14,000 for a new playground. lantana elementary school raised $5358 lantana middle school raised $283
Arada [10]
Total money needed = $14,000
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What is the greatest integer a, such that a^2 + 3b is less than (2b)^2, assuming that b is 5? Please answer and have a nice day!
solniwko [45]
<h3>Answer: Largest value is a = 9</h3>

===================================================

Work Shown:

b = 5

(2b)^2 = (2*5)^2 = 100

So we want the expression a^2+3b to be less than (2b)^2 = 100

We need to solve a^2 + 3b < 100 which turns into

a^2 + 3b < 100

a^2 + 3(5) < 100

a^2 + 15 < 100

after substituting in b = 5.

------------------

Let's isolate 'a'

a^2 + 15 < 100

a^2 < 100-15

a^2 < 85

a < sqrt(85)

a < 9.2195

'a' is an integer, so we round down to the nearest whole number to get a \le 9

So the greatest integer possible for 'a' is a = 9.

------------------

Check:

plug in a = 9 and b = 5

a^2 + 3b < 100

9^2 + 3(5) < 100

81 + 15 < 100

96 < 100 .... true statement

now try a = 10 and b = 5

a^2 + 3b < 100

10^2 + 3(5) < 100

100 + 15 < 100 ... you can probably already see the issue

115 < 100 ... this is false, so a = 10 doesn't work

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What are the outliers in this piece of data?
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