Answer:
b) to produce electrical charges;
Explanation:
Electrical generators are used in a circuit to produce electrical charges. The flow of these charges actually produces electrical energy in a circuit which is needed and essential to power devices and gadgets.
A generator uses mechanical energy through the movement of its parts to produce electrical energy. The flow of electrons streams produces the electrical energy which helps to produce power.
A generator works on the basis of electromagnetic induction using the movement of electric charges.
Answer:
the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
Explanation:
Given the data in the question;
mass m = 1.30 g = 1.30 × 10⁻³ kg
Charge q = +6.90 µC = 6.90 × 10⁻⁶ C
we know that; g = 9.8 m/s
assuming gravity and the electrostatic force are the only forces exerted on the particle, hence the relation is;
F = mg and F = Eq
so
mg = Eq
make E subject of formula
E = mg / q
so we substitute
E = [ (1.30 × 10⁻³) × 9.8 ] / 6.90 × 10⁻⁶
E = 0.01274 / 6.90 × 10⁻⁶
E = 1846.38 N/C
Since the charge is positive ( + ), { direction is Upward }
Therefore, the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
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Answer:
a) wavelengths seen decrease
, b) λ’/λ = 0.9998
Explanation:
a) This is a relativistic doppler effect problem that is described by
f’= f₀ √ (1+ v / c) / √ (1- v / c)
The speed of light be related to wavelength and frequency
c = λ f
f = c /λ
We replace
c /λ’= c /λ √ (1+ v / c) / √(1- v / c)
λ’= λ √ [(1-v / c) / (1 + v / c)]
This expression gives us the wavelength depends on the speed of the premiere with respect to the Earth, as the estuary approaches the Earth the speed is positive
We can see that at the root it is less than 1 whereby the wavelengths seen decrease
b) we reduce the speed to m / s
v = 30 km / s = 3 10⁴ m / s
Change is
λ’/λ = √ [(1-v / c) / (1 + v / c)]
λ’/ λ = √ [(1- 3 10⁴/3 10⁸) / (1 + 3 10⁴/3 10⁸)]
λ’/ λ = √ (0.9999 / 1.0001)
λ’/λ = 0.9998