Answer:
Explanation:
Given
acceleration a =2.2 m/s^2
Force F(t) is given by
F(t)=5.40 t N/s
Power supplied by this force at different time t is given by
Power
velocity at any instant t is given by
v=at
Power
Power
at t=1 s
Power =11.88 W
at t=2 s
Power
at =4 s
Power
Then the object moves in a circle.
Answer:
a)1.51*10^-22joules b) 1.89*10^-7m
Explanation:
Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules
b) net force acting to stop the proton = 8.01*10^-16
Work done needed to stop the proton = net force acting opposite the motion * distance
Distance covered = need work done/ net force
Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m
Answer:
0.99Hz
Explanation:
Using F= -mx ( spring force)
At equilibrium the gravitational force will be balanced by the spring force so mg= kx
K= mg/ 0.25 N/m
But
Frequency f= 1/2pi √g/0.25
Frequency is 0.99Hz