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avanturin [10]
3 years ago
6

Need help with 6th grade math plz help thanks

Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

D.

Step-by-step explanation:

the graph,, top of the graph says year and students enrolled

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Verify the following trig identities​.
bagirrra123 [75]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• 1 + cot² x = csc²x and csc x = \frac{1}{sinx}

• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Consider the left side

sin²Θ( 1 + cot²Θ )

= sin²Θ × csc²Θ

= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified

-----------------------------------------------------------------

Consider the left side

cos²Θ - sin²Θ

= cos²Θ - (1 - cos²Θ)

= cos²Θ - 1 + cos²Θ

= 2cos²Θ - 1 = right side ⇒ verified

3 0
3 years ago
I need help I don't understand
yawa3891 [41]

Answer:

She would charge $39 for 6.5 hours of cleaning

Step-by-step explanation:

Set it up as a proportion: 4.5/27 = 6.5/x

5 0
3 years ago
Read 2 more answers
Please help i am super confused on what to do :)
Ludmilka [50]

Answer:

About 9.1 yards tall.

Step-by-step explanation:

So, we can draw the right triangle shown below:

We want to find h.

Since we know the angle and the side adjacent to the angle and we wan to find the opposite side, we will use the tangent ratio:

\displaystyle \tan(x^\circ)=\frac{\text{Opposite}}{\text{Adjacent}}

So:

\displaystyle \tan(20)=\frac{h}{25}

Therefore:

\displaystyle h=25\tan(20)

Use a calculator. Ensure your calculator is in the correct mode (degrees mode):

h\approx 9.1\text{ yards}

The goal post is around 9.1 yards tall.

7 0
3 years ago
Help plssss and thank you
dimaraw [331]

Answer:

y=\frac{1}{4}x +3

Step-by-step explanation:

slope (rise over run) choose 2 points that are easy to figure out. Count up and over to get the slope

(0,3) and (4,4)

3 to 4 is 1

0 to 4 is 4

slope is 1/4

y intercept is b- so +3

y=y=\frac{1}{4} x+3

5 0
3 years ago
Please help me with both questions!!!!​​
Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a  dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0
3 years ago
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