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3 years ago

In a metallic bond, electrons _____.

2 answers:

Ber [7]3 years ago

7 0

Answer: In covalent bonds electrons are shared. In ionic bonds electrons move from one to another atom. but in Metallic bond, they move freely so the answer is C.

Nady [450]3 years ago

3 0

Answer is C i hope this helps!

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At a certain temperature, the percent dissociation (ionization) of chlorous acid, HClO2, in a 1.43 M solution water is 8.0%. Cal

lakkis [162]

Answer:

Kₐ = 9.9 × 10⁻³

Explanation:

HClO₂ + H₂O ⇌ H₃O⁺ + ClO₂⁻

0.080 × 1.43 = 0.1144

So, at equilibrium,

[H₃O⁺] = [ClO₂⁻] = 0.1144

[HClO₂] = 1.43 – 0.1144 = 1.316

Kₐ = {[H₃O⁺][ClO₂⁻]}/[HClO₂]; Substitute values

Kₐ = (0.1144 × 0.1144)/1.316 Do the operations

Kₐ = 9.9 × 10⁻³

5 0

3 years ago

The smallest particle of an element that retains the properties of that element is a(n)

alekssr [168]

Answer: atom

Explanation:

It makes the most sense to me anyways seeing that an atom contains protons electrons and neutrons in it already

4 0

3 years ago

What is the number of collaborative relationships he creates

Bond [772]

Answer:

answer is 60

Explanation:

3 0

2 years ago

A graduated cylinder is filled 241.5 ML with water and a piece of granite is placed in the cylinder displacing the level 247.6 M

NikAS [45]

Answer:

6.1 cm³

Step-by-step explanation:

Cylinder + water + granite = 247.6 mL

-(Cylinder + water) = 241.5 mL

Granite = 6.1 mL

1 mL = 1 cm³, so

Volume of granite = 6.1 cm³

3 0

3 years ago

A chemist prepares a solution of iron(II) bromide FeBr2 by measuring out 224.g of iron(II) bromide into a 300.mL volumetric flas

gulaghasi [49]

Answer: The molarity of iron(II) bromide solution is 3.46 M

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of iron(II) bromide = 224. g

Molar mass of iron(II) bromide = 215.65 g/mol

Volume of solution = 300. mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{224\times 1000}{215.65g/mol\times 300}\\\\\text{Molarity of solution}=3.46M$

Hence, the molarity of iron(II) bromide solution is 3.46 M

5 0

4 years ago