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noname [10]
2 years ago
15

____ ha no nucleus.

Chemistry
2 answers:
Serga [27]2 years ago
7 0

I think its prokaryotes?

SVETLANKA909090 [29]2 years ago
5 0
Prokaryotes...hope this helped
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Octane (C8H18)reacts oxygen gas (O2) to form carbon dioxide and water
iren [92.7K]

Answer:

i believe this is true

Explanation:

5 0
3 years ago
How many grams are 1.20 x 1025 molecules of calcium iodide?
jeka57 [31]

Answer:

1230

Explanation:

1.20×1025=1230 is your answer

5 0
2 years ago
Select the true statements regarding these resonance structures of formate.? Each carbon-oyxgen bond is somewhere between a sing
son4ous [18]

Answer : Option 1) The true statement is each carbon-oxygen bond is somewhere between a single and double bond and the actual structure of format is an average of the two resonance forms.

Explanation : The actual structure of formate is found to be a resonance hybrid of the two resonating forms. The actual structure for formate do not switches back and forth between two resonance forms.

The O atom in the formate molecule with one bond and three lone pairs, in the resonance form left with reference to the attached image, gets changed into O atom with two bonds and two lone pairs.

Again, the O atom with two bonds and two lone pairs on the resonance form left, changed into O atom with one bond and three lone pairs. It concludes that each carbon-oxygen bond is neither a single bond nor a double bond; each carbon-oxygen bond is somewhere between a single and double bond.

Also, it is seen that each oxygen atom does not have neither a double bond nor a single bond 50% of the time.

7 0
3 years ago
Read 2 more answers
The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?
Nat2105 [25]
To answer the problem above first we need to find the difference of molar mass of NI3 from I2, 394.71 g/mol - 253.80 g/mol = 140.91 g/mol. Knowing the molar mass of the difference of NI3 from I2, in equation mass (g) / moles (mol) = molar mass, then we substitute. 3.58g / moles = 140.91 g/mol.
moles = 3.58 / 140.91 = 0.025 moles.
6 0
3 years ago
What was the weight percent of water in the hydrate before heating?
DedPeter [7]
Data:

weight of water before heating = 0.349

weight of hydrate before heateing = 2.107

Formula:

Weight percent of water = [ (weight of water) / (weight of the hydrate) ] * 100

Solution:

Weight percent of water = [ 0.349 / 2.107] * 100 ≈ 16.6 %

Answer: 16.6%
3 0
3 years ago
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