Answer:
0.5 mole of CO₂.
Explanation:
We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:
Mass of NaHCO₃ = 42 g
Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)
= 23 + 1 + 12 + 48
= 84 g/mol
Mole of NaHCO₃ =?
Mole = mass / molar mass
Mole of NaHCO₃ = 42/84
Mole of NaHCO₃ = 0.5 mole
Next, balanced equation for the reaction. This is given below:
NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂
Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.
Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.
Thus, 0.5 mole of CO₂ was obtained from the reaction.
is 44 g/mol and molar mass of
is 18 g/mol
