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Hoochie [10]
3 years ago
15

jack paid $64 for two algebra and three geometry books. he paid $66 for three algebra and two geometry books. what is the cost o

f each book ?
Mathematics
1 answer:
kap26 [50]3 years ago
4 0
Lets make the cost of the algebra textbook = x and the cost of the geometry book = y

2x+3y=64
4x+2y=66

now we get one of these equations in terms of one variable

2x+3y=64 ---> 2x=64-3y ---> x=32-1.5y

now we can plug that numeric value back into the other equation

4(32-1.5y)+2y=66

we can now simplify this equation in order to get the value of y

4(32-1.5y)+2y=66 ---> 128-6y+2y=66 ---> 128-4y=66 ---> -4y=-64 ---> y=16
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First of all, we need all logarithms to have the same base. So, we use the formula

\log_a(b)=\dfrac{\log_c(b)}{\log_c(a)}

To change the second term as follows:

\log_4(x^2)=\dfrac{\log_2(x^2)}{\log_2(4)}=\dfrac{\log_2(x^2)}{2}

Finally, using the property

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we have

\dfrac{\log_2(x^2)}{2}=\log_2(x)

So, the equation becomes

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Now consider both sides as exponents of 2:

\dfrac{3x+4}{x^6}=4 \iff 4x^6-3x-4=0

This equation has no "nice" solution, so I guess the problem is as simplifies as it can be

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