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vladimir2022 [97]
3 years ago
11

Suppose you have a 1/10 chance of winning with a scratch-off lottery ticket. If you buy 4 tickets, what is the probability of wi

nning with all 4?
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
4 0
1/10 chance on winning with 1 ticket...so winning with 4 tickets = 
1/10 * 1/10 * 1/10 * 1/10 = 1/(10^4) = 1/10,000
nirvana33 [79]3 years ago
3 0

Answer:

1/10000

Step-by-step explanation:

Suppose you have a 1/10 chance of winning with a scratch-off lottery ticket.

If you buy 4 tickets

Probability of winning 1 ticket = 1/10

For 4 tickets we find the probability of every ticket

probability (winning first ticket)=1/10

probability (winning 2nd ticket)=1/10

probability (winning 3rd ticket)=1/10

probability (winning 4th ticket)=1/10

P(winning all 4) = \frac{1}{10} *\frac{1}{10} *\frac{1}{10} *\frac{1}{10} = \frac{1}{10000}

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Alex, Bob, and Claudia split 126 cm wire evenly among themselves. They then proceeded to cut their pieces of wire into smaller,
Westkost [7]
<h3>Answer:</h3>
  • Bob
  • 18 cm
<h3>Step-by-step explanation:</h3>

If Alex cut his wire 18 times, he ended up with 19 equal pieces. He kept 7, so has 7/19 of his 1/3 of the wire.

Bob cut his wire 20 times, so ended up with 21 pieces, of which he kept 9. So he has 9/21 = 3/7 of his 1/3 of the wire.

Claudia kept 1/13 of her 1/3 of the wire, so has the smallest piece.

Bob kept (3/7)·(1/3)·126 cm = 18 cm.

Alex kept (7/19)·(1/3)·126 cm ≈ 15.47 cm.

Bob kept the longest part of the original wire.

3 0
3 years ago
Help, please! 10 points to solve.
sineoko [7]
The answer is B, 7.6-(-1.7)=9.3
6 0
3 years ago
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Fiesta28 [93]

Answer:

The sample has not met the required specification.

Step-by-step explanation:

As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow

H_0: The true average penetration is 50 mils

H_a: The true average penetration is > 50 mils

Since we are trying to see if the true average is greater than 50, this is a right-tailed test.

If the <em>level of confidence</em> is α = 0.05 then the z_\alpha score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)

The z-score associated with this test is

z=\frac{\bar x-\mu}{s/\sqrt{n}}

where

\bar x = <em>mean of the sample</em>

\mu = <em>average established by the specification</em>

s = <em>standard deviation of the sample</em>

n = <em>size of the sample</em>

Computing this value of z we get z = 3.42

Since z >z_\alpha we can conclude that the sample has not met the required specification.

5 0
3 years ago
The average hourly charge of plumbers in the Denver area is $84.00 with a standard deviation of $4.00. Assume that the hourly ch
Simora [160]

Answer:

The probability is 0.31

Step-by-step explanation:

In this question, we are tasked with calculating the probability that a random plumber called at Denver will charge an amount greater than $86 given the mean and the standard deviation.

Firstly, we calculate the standard score of $86 using the mean and the standard deviation.

Mathematically;

z-score = (x-mean)/SD

where x = 86, mean = 84 and SD = 4

z-score = (86-84)/4 = 2/4 = 0.5

Hence, we want to calculate P(z ≥ 0.5)

Using standard table

P( (z ≥ 0.5) = 1 - P(z ≤ 0.5) = 1 - ( 0.19146 + 0.5) = 0.30854

To the nearest hundredth = 0.31

5 0
3 years ago
Someone plsss help ASAP I give points
disa [49]

Answer:

90

Step-by-step explanation:

6 0
2 years ago
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