Why is it incorrect to say <img src="https://tex.z-dn.net/?f=d%20%3D%202r" id="TexFormula1" title="d = 2r" alt="d = 2r" align

Pls do it for me thank you so much

Bond [772]

Answer:

(a) Attached to this response.

(b)

(i) 0 cups = 0.275

(ii) 4 cups = 0.125

(iii) 8 cups = 0.025

Step-by-step explanation:

(a) The frequency and relative frequency table has been attached to this response.

i. The first column, labelled x, is the number of cups of coffee consumed per day.

ii. The second column, labelled f, is the number of people that consumed x cups of coffee per day. It is found by counting the number of occurrences (i.e frequency) of the numbers of the first column, x, in the given data.

For example, 0 in first column appears 11 times in the given data. Also, 5 in the first column appears 4 times in the given data.

iii. The third column, labelled r, is the relative relative frequency of the number of cups of coffee. It is calculated by dividing the frequency of the cups of coffee by the total number of people that consumed it. As shown on the table, it is calculated by dividing the each of the values on the second column by the sum of the values on that same column (second column).

For example, the relative frequency of 2 cups of coffee is given by:

r = 7 ÷ 40 = 0.175

Also, the relative frequency of 4 cups of coffee is given by;

r = 5 ÷ 40 = 0.125

(b) The probability (Pₓ) that a randomly selected person consumed x cups of coffee is given by;

Pₓ = frequency of x ÷ total frequency

This is also the relative frequency of x

Therefore,

(i) The probability (P₀) that a randomly selected person consumed 0 cups of coffee is given by;

the relative frequency of 0 = 0.275

(ii) The probability (P₄) that a randomly selected person consumed 4 cups of coffee is given by;

the relative frequency of 4 = 0.125

(iii) The probability (P₈) that a randomly selected person consumed 8 cups of coffee is given by;

the relative frequency of 8 = 0.025

Download docx

5 0

4 years ago

Tommy has 6 more than 3 times the amount of money in his bank account than Judy. Judy has $7500 more than a number in her accoun

Ad libitum [116K]

Answer:

Amount of money Judy has in her account is $\$(7500+n)$ .

Amount of money Tommy has in his account is $\$(22506+3n)$

Step-by-step explanation:

To find : Amount of money in Judy account and amount of money in Tommy account:

Solution:

Given:

Judy has $7500 more than a number in her account.

Let the number be 'n'.

So we can say that;

Amount of money in Judy account is equal to 7500 plus number.

framing in equation form we get;

Amount of money in Judy account = $\$(7500+n)$

Hence Amount of money Judy has in her account is $\$(7500+n)$ .

Now Given:

Tommy has 6 more than 3 times the amount of money in his bank account than Judy.

So we can say that;

Amount of money in Tommy account is equal to 3 multiplied by Amount of money in Judy account plus 6.

framing in equation form we get;

Amount of money in Tommy account = $3(7500+n)+6 =22500+3n+6=\$(22506+3n)$

Hence Amount of money Tommy has in his account is $\$(22506+3n)$ .

8 0

3 years ago

A winter resort took a poll of its 400 visitors to see which winter activities people enjoyed. The results were as follows: 188

VARVARA [1.3K]

Exactly one activity: 246
None of the activities : 1
At least one activity: 74
Snowboarding and Ice skating but not skiing: 5
Snowboarding or ice skating but not skiing: 132.
Only skiing : 119.
The diagram is in the attachment.

Download docx

6 0

3 years ago

Need help don’t know what I’m doing

docker41 [41]

This problem mean you have to find the point that the Domain and Range is suit (I'm sorry English is my second language)
Example:
1) G ; 2) Y
If you want me to do the rest of it tell me Okay ^^

8 0

3 years ago

Find the t-value such that the area in the right tail is 0.005 with 28 degrees of freedom.

klasskru [66]

Answer:

$t = 3.673900$