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olya-2409 [2.1K]
3 years ago
7

Henry was able to help 4 out of 9 of students that requested help in the math lab and Michelle helped 45% of the total students

who asked for help. Who helped more students, Henry or Michelle?
Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0
For Henry: 4 out of 9 is equal to 4 divided by 9. That gives you approximately 0.444. Multiply that by 100 to get the percentage and you get 44.4%.

Henry: 44.4%
Michelle 45%

MICHELLE HELPED MORE STUDENTS
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A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit
aliina [53]

Answer: All possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

2x+9y=101

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

7 0
3 years ago
PLEASE ANSWER ASAP!!!
julsineya [31]

Answer:

The answer to your question is A) x = 1

Step-by-step explanation:

We know that f(x) = 2x + 3 and g(x) = -x + 6

But   f(x) = g(x)

Then,                          2x + 3 = - x + 6

                                   2x + x = 6 - 3

                                         3x = 3

                                          x = 3/3

                                          x = 1

The solution is circle in the graph below.

8 0
3 years ago
Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000 If we record the se
lys-0071 [83]

Answer:

The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000

Sample of 40

Shape approximately normal

Mean 350000

Standard deviation s = \frac{160000}{\sqrt{40}} = 25298

The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

5 0
3 years ago
Read 2 more answers
Can someone please do this for me
Natasha_Volkova [10]
Next time please indicate which problem you want to work on.

One example of an equation with variables present on both sides is

y-b = m(x-a).  Given the slope of a line and one point (a,b) through which the line passes, you can come up with an equation of the line.

Or, given the numeric value of y-b and that of x-a, you could obtain the slope of the line thru the points (x,y) and (a,b).
7 0
3 years ago
Juan wants to start a lemonade stand to earn money. He needs money to purchase the materials before he can sell the lemonade and
enot [183]

Answer:

a. $13

b. $3

Step-by-step explanation:

Juan wants to start a lemonade stand to earn money. He needs money to purchase the materials before he can sell the lemonade and earn money. His mother agrees to loan him $10. He makes a list of the items he wants to buy.

Cups $2

Lemons $8

Sugar $3

a. How much money do the supplies cost?

b. How much money does he have to spend?

a. Cost of each supply;

Cups $2

Lemons $8

Sugar $3

Total cost of the supplies = $2 + $8 + $3

= $13

b. How much money does he have to spend?

His mother agreed to loan him $10

Total cost of supplies = $13

Amount of money he has to spend = Total cost of supplies - Loan from his mother

= $13 - $10

= $3

7 0
3 years ago
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