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3 years ago

Which of the equations below represents a line perpendicular to the y-axis?

Mathematics

2 answers:

timurjin [86]3 years ago

7 0

Answer:

B. y = -6

Step-by-step explanation:

As you can see the graph I done is perpendicular

Olenka [21]3 years ago

4 0

Answer:

Step-by-step explanation:

A line perpendicular to the y- axis is a horizontal line parallel to the x- axis, with equation

y = c ( where c is the value of the y- coordinates the line passes through )

The only equation in this form is

y = - 6 → B

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PLEASE HELP ANSWER THESE QUESTIONS!

Sliva [168]

Answer:

Step-by-step explanation:

a² - b² = (a+ b)(a - b)

1) (2n-4/2n) ÷ (n^2-4/n)

$=\frac{2n-4}{2n}*\frac{n}{n^{2}-4}\\\\=\frac{2n-2*2}{2n}*\frac{n}{n^{2}-2^{2}}\\\\=\frac{2*(n-2)}{2n}*\frac{n}{(n+2)*(n-2)}\\\\=\frac{1}{n+2}$

2) [y^2-36/y^2-49] ÷[ y+6/y-7]

$=\frac{y^{2}-36}{y^{2}-49}*\frac{y-7}{y+6}\\\\=\frac{y^{2}-6^{2}}{y^{2}-7^{2}}*\frac{y-7}{y+6}\\\\=\frac{(y+6)*(y-6)}{(y+7)*(y-7)}*\frac{y-7}{y+6}\\\\=\frac{y-6}{y+7}\\$

3) [m^2-1/ m^2-m] ÷ [m^2-7m-8/3m ]

$=\frac{m^{2}-1}{m^{2}-m}*\frac{3m}{m^{2}-7m-8}\\\\=\frac{(m+1)*(m-1)}{m*(m-1)}*\frac{3m}{(m-8)*(m+1)}\\\\=\frac{3}{m-8}$

Hint : m² - 7m - 8

sum = -7

Product = -8

Factor = (-8), 1

m² - 7m - 8 =m² - 8m + m - 8

= m*(m - 8) + (m-8)

= (m - 8)(m +1)

7 0

3 years ago

Please tell me what x is 3(x+6)=48

Alekssandra [29.7K]

Answer

X=10

Step by step explanation

48÷3 = 16

16-6 = 10

7 0

4 years ago

Solve the system of linear equations by elimination.<br> 5 - 2y = -8<br> 4x – 4y= 8

Alenkasestr [34]

Answer:

x = 17/2

y = 13/2

Step-by-step explanation:

Hope this helps!

6 0

3 years ago

I’ll give brainlinest

Mama L [17]

Answer:

what do you need help with

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which section of the function is constant? A graph is shown. Segment A begins at the origin and continues upward. Segment B cont

ad-work [718]

I believe its B, since its constant.

If that helped make sure to mark brainliest!
-procklown

6 0

3 years ago