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charle [14.2K]
3 years ago
14

Factorise x squared - 12x + 36

Mathematics
1 answer:
slava [35]3 years ago
3 0

Answer:

(x-6)(x-6) or (x-6)^2

Step-by-step explanation:

x^2-12x+36=(x-6)(x-6)

Just find two numbers that when they multiply, you get the third term,

which is 36 in this case. And when they add up, you get the second term,

which is -12 in this case. You can also check the answer by multiplying.

(x-6)(x-6)=x^2-6x-6x+36=x^2-12x+36

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Answer:

circle b and it is bigger by 1 centimeter

Step-by-step explanation:

since circle b has a radius of 5 and radius is have of the diameter you have to do 5+5 to get the diameter when you do that you get 10 and then you have to subtract circle a diameter which is 9 from circle b diameter which is 10 so 10-9 is 1

4 0
3 years ago
4y-14=18. Hahahahahahahaahahaha
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Answer:

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3 years ago
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A horticulturist working for a large plant nursery is conducting experiments on the growth rate of a new shrub. Based on previou
valkas [14]

Answer:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

Step-by-step explanation:

Information given

\bar X=1.8 represent the sample mean for the growth

s=0.5 represent the sample standard deviation    

n=48 sample size    

\mu_o =2 represent the value that we want to compare

\alpha=0.01 represent the significance level

t would represent the statistic    

p_v represent the p value

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 2cm per week, the system of hypothesis are :    

Null hypothesis:\mu \geq 2    

Alternative hypothesis:\mu < 2    

Since we don't know the population deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing the info given we got:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

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igor_vitrenko [27]
Your answer is C) because it is in between
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2 years ago
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