<span>The number of worksheets a workbook can contain is limited to the memory of your computer.
The computer memory denotes the </span><span>hardware integrated circuits in the computer. These circuits store information for immediate use in a </span><span>computer, for worksheets for example.</span>
Answer:
Option a. int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }
is the correct code snippet.
Explanation:
Following is given the explanation for the code snippet to find largest value in an integer array list aList.
- From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
- By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
- If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
- When the loop will end, the variable max will have the greatest value from the array aList.
i hope it will help you!
Ooh, ooh, ooh I know this one!
One advantage is that you don't have to make the entire layout of what you are doing from scratch. It is also time saving by not making you write everything.
Answer:
The correct answer to the following question will be "Physical".
Explanation:
- The lowest layer of the OSI model is the physical layer. It's in charge of transferring bits through one device to the next.
- This layer isn't worried about the importance of the components and deals with setting up a connection to the node of the network and transmitting and receiving a signal.
Therefore, the Physical layer is the right answer.
Var<span> person = prompt(</span>"Please enter your name"<span>, </span>"Name Field"<span>);
<span>Though, this might be in the wrong context.</span></span>
