Answer:
optionb
Step-by-step explanation:
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
Joubert hint all ineyzreytfcfvbubu equals 9
Answer:
C
Step-by-step explanation:
A =
r²
so we do
5² = 25 * 
25 * 
= 78.5 square units
Answer:
.
Step-by-step explanation:
A point of the form
belongs to the graph of this function,
, if and only if the equation of this function holds after substituting in
and
.
The question states that the point
belongs to the graph of this function. Thus, the equation of this function,
, should hold after substituting in
and
:
.
.
Solve this equation for the constant
:
.
Thus,
.