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Ostrovityanka [42]
3 years ago
14

What is the answer?

Mathematics
1 answer:
mezya [45]3 years ago
5 0

Answer:

18.1 cm

Step-by-step explanation:

AD segment breakup: 11=4+7

Pythagorean Theorem:

7^2+b^2=16^2

49+b^2=256

x^2=207

b=sqrt(207)

b=3sqrt(23)

Pythagorean Theorem:

11^2+3sqrt(23)^2=c^2

121+207=c^2

328=c^2

18.11=c

So the length of AC is around 18.1 cm

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Can someone pls pls PLS, help me out? ASAP!! (Geometry)<br> “Complete the proof”
Maru [420]

1) \overline{AB} \perp \overline{BD}, \overline{AB} \cong \overline{DB}, \overline{AC} \cong \overline{DE} (given)

2) \angle ABD is a right angle (perpendicular lines form right angles)

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1 year ago
The coordinates of point A on a coordinate grid are (−2, −3). Point A is reflected across the y-axis to obtain point B and acros
amid [387]

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B) B(2,-3) and C(-2,3)

Step-by-step explanation:

The given point A, has coordinates (-2,-3).

When point A(-2,-3) is reflected over the y-axis to obtain point B, then the coordinates of B is obtained by negating the x-coordinate of A.

Therefore B will have coordinates (2,-3).

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3 0
3 years ago
what is the distance between the points (23,-33) and (4,9) if necessary round your answer to two decimal places
Rufina [12.5K]

The distance between the points (23,-33) and (4,9) rounded to two decimal places is 46.10.

<h3>What is the distance between the points (23,-33) and (4,9)?</h3>

The distance between two points on a graph can be determined using the equation;

D = √[ ( x₂ - x₁ )² + ( y₂ - y₁ )² ]

Given that;

  • x₁ = 23
  • x₂ = 4
  • y₁ = -33
  • y₂ = 9

We substitute our values into the equation above.

D = √[ ( x₂ - x₁ )² + ( y₂ - y₁ )² ]

D = √[ ( 4 - 23 )² + ( 9 - (-33) )² ]

D = √[ ( -19 )² + ( 42 )² ]

D = √[ 361 + 1764 ]

D = √[ 2125 ]

D = 46.10

Therefore, the distance between the points (23,-33) and (4,9) rounded to two decimal places is 46.10.

Learn more about distance formula here: brainly.com/question/7592016

#SPJ1

7 0
2 years ago
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