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andriy [413]
4 years ago
12

Marcos is organizing a fundraiser for his youth group. If he spent $38.00 on paper products, $187.00 on food, and $40.00 on deco

rations, how much money did he spend?
$165.00
$265.00
$155.00
$255.00
Mathematics
2 answers:
Citrus2011 [14]4 years ago
6 0
The correct answer is $265
lys-0071 [83]4 years ago
3 0
If he bought all that then he would have spent 265$
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If f(x)=2x^4-3x^3+2x^2+x-3, explain how you know that the equation f(x)=0 has at least one real root between x=1 and x=2
hodyreva [135]

Answer:

Step-by-step explanation:

by theorem :

f continu in [1 , 2]

f(1)×f(2) < 0 because : f(1) = -1 and f(2) = 15

so the equation f(x)=0 has at least one real root between x=1 and x=2

so :

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Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at
kari74 [83]

Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event  

- The probability of an Event = Number of favorable outcomes ÷ Total

 number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A  

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

  choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

3 0
3 years ago
Read 2 more answers
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Naddik [55]
A parachute was used
6 0
3 years ago
What's equivalent to 9/15
yan [13]
A fraction equivalent to 9/15 is 3/5

To find equivalent fractions, you have to find a a divisor that both the numerator and denominator has. Then you divide the numerator and denominator by that divisor.

Example: 9 and 15 are divisible by 3.
 9 is the numerator.9 divided by 3 is 3. so the numerator of the equivalent fraction is now 3.
15 is the denominator. 15 divided by 3 is 5. the denominator is now five.

Hope this helps! :)

7 0
3 years ago
Read 2 more answers
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