1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Norma-Jean [14]
3 years ago
15

What is the total amount of a new vehicle if the standard vehicle price is $14,530 options cost $1,717 and a destination charge

of $445?
Mathematics
1 answer:
Vlada [557]3 years ago
4 0
For this case, the total amount is the sum of all costs.
 We have then:
 total amount = standard vehicle price + options cost + destination charge
 Substituting values we have:
 total amount = 14530 + 1717 + 445
 total amount = 16692 $
 Answer:
 
The total amount of a new vehicle is:
 
total amount = 16692 $
You might be interested in
On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre
Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}

P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}

P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0
3 years ago
The volume of a pyramid varies jointly with the base area of the pyramid and its height. The volume of one pyramid is 35 cubic i
Alla [95]
You first might want to divide 36 by 3, giving you 12. Multiply 12 by 5, which results in your answer of 60in^3. The equation for this is V = 1/3(blh)
6 0
3 years ago
Given:<br> cos(2x)=-1/9<br> Angle x is in quadrant I.<br> Find:<br> cos(x)
sergey [27]
My opinion about this answer is 7
5 0
3 years ago
WILL GIVE BRAINLIST
Otrada [13]

Answer:

I think it will be combined and simplified

5 0
3 years ago
Read 2 more answers
5 times a number is 24 less than the square of that number
AlekseyPX

Answer:

5x<x^2-24

Step-by-step explanation:

pretty sure that's right and the x^2 that's an exponent :)

7 0
3 years ago
Other questions:
  • Which names are other ways to name ∠1?
    15·1 answer
  • An irregular parallelogram rotates 360 degrees about the midpoint of its diagonal. How many times does the image of parallelogra
    15·1 answer
  • ______________________________________________________________________________________
    5·2 answers
  • Suppose you have a $60,000 loan with an annual percentage rate of 8% for 25 years.
    6·1 answer
  • Michelle cut 1/4 yard of ribbon into 4 equal pieces what is the length of each equal piece
    11·1 answer
  • Which decimal is greater 0.7 or 0.07?
    15·2 answers
  • John spent about 12 hours at a water park. He estimated he spent about 40% of the time waiting in line. What would be a reasonab
    12·1 answer
  • Plz help and dont put links to bad sites
    11·2 answers
  • someone help. i can’t seem to figure this out, it’s simple math but i just don’t understand it i need the answer as soon as poss
    15·1 answer
  • Saul wants to bike 48 kilometers to taste some really good mangoes.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!