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Norma-Jean [14]
3 years ago
15

What is the total amount of a new vehicle if the standard vehicle price is $14,530 options cost $1,717 and a destination charge

of $445?
Mathematics
1 answer:
Vlada [557]3 years ago
4 0
For this case, the total amount is the sum of all costs.
 We have then:
 total amount = standard vehicle price + options cost + destination charge
 Substituting values we have:
 total amount = 14530 + 1717 + 445
 total amount = 16692 $
 Answer:
 
The total amount of a new vehicle is:
 
total amount = 16692 $
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The New England patriots scored 9 points in the first half. In the second half they scored 3 less than 2 times the points in the
Rom4ik [11]

Answer:

S : T = 5 : 8

Step-by-step explanation:

Represent the first half with F and the second with S

We have that:

F = 9 --- From the first statement

S = 2F - 3 --- From the next statement

Required

Determine the ratio of S to the total point

First, we need to determine the value of S

Substitute 9 for F in S = 2F - 3

S = 2 * 9 - 3

S = 18 - 3

S = 15

Next, we determine the total points

Total =  F + S

Total =  9 + 15

Total =  24

The ratio of S to total is: (Represent total with T)

S : T = 15 : 24

Divide both ration by 3

S : T = 15/3 : 24/3

S : T = 5 : 8

<em>Hence, the ratio is 5 to 8</em>

4 0
3 years ago
Math Questions :3 thank uu &lt;3
coldgirl [10]
14.       1.5, 10    <- Answer
15.       5,1          <- Answer

Proof 14 

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5               
                y = 10

Proof 15. 

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer:  {x = 5                           y = 1
8 0
3 years ago
What is the answer to 3x + 1? (giving brainliest to whoever can solve this)
yan [13]

Step-by-step explanation:

3x + 1

=3x + 1

this is because a variable X is attached to the 3 so it makes the 3x and the 1 unlike

therefore you can not add them.

6 0
2 years ago
Read 2 more answers
Certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours. Find the probabi
Anna71 [15]

Answer:

Step-by-step explanation:

given that certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours.

Sample size n =16

Std error of sample mean = \frac{\sigma}{\sqrt{n} } \\= 15

x bar follows N(800, 15)

the probability that a random sample of 16 tubes taken from the group will have a mean lifetime

(a) between 790 and 810 hours,

=P(790

(b) less than 785 hours

=P(X

, (c) more than 820 hours,

=P(X>820)\\=p(Z>1.333)\\= 0.0913

(d) between 770 and 830 hours

=P(|Z|

4 0
3 years ago
Determine whether the random variable is discrete or continuous. In each​ case, state the possible values of the random variable
Advocard [28]

Answer:

a. Discrete

b.Continuous

Step-by-step explanation:

a. A discrete random variable has a countable number of possible values.

-The probability of each value of a discrete random variable is between 0 and 1, and the sum of all the probabilities is equal to 1.

-The number of free dash throw attempts are countable. Hence, a Discrete Random Variable.

b. -A continuous random variable is a random variable where the data can take infinitely many values.

-A continuous random variable is a random variable is qualitative in nature.

-The amount of rainfall will take different values in different April months. Hence Continuous Random Variable.

5 0
3 years ago
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