Given =
Two similar pyramid have base area of 12.2 cm² and 16 cm².
surface area of the larger pyramid = 56 cm²
find out the surface area of the smaller pyramid
To proof =
Let us assume that the surface area of the smaller pyramid be x.
as surface area of the larger pyramid is 56 cm²
Two similar pyramid have base area of 12.2 cm² and 16 cm².
by using ratio and proportion
we have
ratio of the base area of the pyramids : ratio of the surface area of the pyramids
x = 12.2 ×56×
by solvingthe above terms
we get
x =42.7cm²
Hence the surface area of the smaller pyramid be 42.7cm²
Hence proved
Answer:
93.4 g/mL x 20. mL = 1868g.
489.7m / 53.061 s = 9.23 m/s
216.3 m/66.4 s = 3.26 m/s.
Step-by-step explanation:
Let's analyze each case.
93.4 g/mL x 20. mL
Hewe we are multiplying g/ml*ml. So we have the answer is (g*ml/ml) = g.
So
93.4 g/mL x 20. mL = 1868g.
489.7m / 53.061 s
We are dividing a measurement in m by a measurement in s. So the answer is in m/s.
So
489.7m / 53.061 s = 9.23 m/s
216.3 m/66.4 s
Same as above.
We are dividing a measurement in m by a measurement in s. So the answer is in m/s.
So
216.3 m/66.4 s = 3.26 m/s.
Answer:
slope (m) = 1 and intercept = -4
Step-by-step explanation:
comparing with Y = mX - c
It increases the mean value of the prizes.
Answer:
-1/2
Step-by-step explanation:
