Answer:
y=27 when x=2
Step-by-step explanation:
y varies inversely as the cube of x
y=k(1/X^3)
y=1 when x=6
y=k(1/X^3)
1=k(1/6^3)
1=k(1/216)
k=1÷1/216
K=1×216/1
k=216
find y when x=2
y=k(1/X^3)
y=216(1/2^3)
y=216(1/8)
y=216/8
y=27
First we need to isolate the variable so we add 15 to both sides which is
w/4=43 then we need to multiply by 4 to both sides so its 4w=172
then divide by 4 which is 43 so the answer is w=43
Answer:
The answer is 3 7/12 Hope this helps :)
Step-by-step explanation:
Answer:
x =±2 sqrt(6)
Step-by-step explanation:
x^2 = 24
Take the square root of each side
sqrt(x^2) = sqrt(24)
x = ±sqrt(4*6)
x =±sqrt(4) sqrt(6)
x =±2 sqrt(6)
YOU CAN DO Y=MX+B AND YOU WILL FIND YOUR ANSWER
