The answer would be D, 12 units! :)
Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
Answer:
k=10
Step-by-step explanation:
g(x)=2x^2+ kx+18
when x=-2
g(-2)=2 (-2)^2 -2k +18
Since when x is -2, y =6
6=2 (-2)^2 -2k +18
6=18+8-2k
2k=26-6
2k=20
k=10
Answer:
No you wouldn't because you are not dividing or multiplying by a negative number.
Step-by-step explanation:
1/4 of 20 is 5.
You divide 20 by 4.
Then you get 5, which is your final answer.
Have a nice day!