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Ahat [919]
3 years ago
6

How can you use absolute value to represent a negative number in real World situation?

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0
Maybe when you give people money 
then they have to pay you so that is 
negetive to you till when you get it back
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Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.
kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = \frac{38}{60} = 0.634

Therefore, the probability is given by:

P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]

P(p\leq 0.634) = P[z\leq -1.87188]

P(p\leq 0.634) = P[z\leq -1.87] = 0.0298

Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

6 0
3 years ago
Legs 3 and 4 are present what is the hypotenuse?
andrew11 [14]

Answer:

4 is hypotenuse

Step-by-step explanation:

6 0
3 years ago
Describe the varying vegetation regions in Canada
pantera1 [17]

Answer: Canada Vegetation

Forests are primarily mixes of white and black spruce, lodgepole pine, balsam poplar, paper birch and trembling aspen. Common understorey plants include mountain and green alders, highbush cranberry, wild rose, Canadian buffalo berry and reed grass, fireweed, lingonberry, twinflower and feather mosses.

8 0
2 years ago
Read 2 more answers
A random sample of 864 births in a state included 426 boys. Construct a 95% confidence interval estimate of the proportion of bo
oksian1 [2.3K]

Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:

n = 864, \pi = \frac{426}{864} = 0.493

Then, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 - 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.46

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 + 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.526

The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
What percent of workers have output more than 70 units?
ivann1987 [24]

Answer:

30%

Step-by-step explanation:

6 0
3 years ago
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