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Anon25 [30]
3 years ago
15

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

21

Step-by-step explanation:

The 5 smallest prime numbers are 1, 2, 3, 5, and 7.

So when multiplied it equals 105.

Divide by 42 and you get 2 21/42

So you have a remainder of 21

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8 + 5n - 6, use n = 6
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32 is the answer.

I hope this helps!
~kaikers
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3 years ago
Can u guys help me with #1
Furkat [3]

Answer: 4 1/2 cups


Step-by-step explanation: Half a cup per flower, one cup per 2 flowers. 2x4 = 8 flowers so thats 4 cups plus the half a cup

5 0
3 years ago
A right triangle has two sides equal to 8 units and 17 units. Which could be the length of the third side of this triangle?
charle [14.2K]

Answer:

15 units

Step-by-step explanation:

8 0
2 years ago
Can some one answer quickly please
denis-greek [22]

Answer:

the answer is A -1/3 x

Step-by-step explanation:

hope this helps :)

3 0
3 years ago
WILL GIVE BRAINLIEST TO BEST RESPONSE!
Monica [59]

You are given the X value, replace x with 2 in the first equation to solve for y:

y=2x +3

y = 2(2) +3

y = 4+3

y = 7

Now replace y with 7 and x iwth 2 in the second equation and solve for k:

y = -x +k

7 = -2 +k

Add 2 to both sides:

9 = k

so k = 9

The point is given as k-2, which is 9-2 = 7, which is what y equals in the first equation.

K = 9

5 0
3 years ago
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