What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

The 5 smallest prime numbers are 1, 2, 3, 5, and 7.

So when multiplied it equals 105.

Divide by 42 and you get 2 21/42

So you have a remainder of 21

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David’s bowling score is 5 less than 3 times Aaron’s score. The sum of their score is 215. Find the score of each student. Write

xenn [34]

Answer:

David's score= 160 ; Aaron's score = 55

Step-by-step explanation:

let Aaron's score be 'x'.

so, David's score will be 3x - 5

(3x - 5) + x = 215

3x + x - 5 = 215

4x = 215 + 5

4x = 220

x = 220/4

x = 55

therefore, Aaron's score = 55

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borishaifa [10]

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KATRIN_1 [288]

*the table being referred to is attached below

Answer:

The table does not show a proportional relationship between variable g and h.

Step-by-step explanation:

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Thus, in the table attached below, there is no obvious constant of proportionality between variable g and variable h.

Thus, $\frac{9}{3}$ ≠ $\frac{36}{6}$ ≠ $\frac{81}{9}$