3 years ago

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

The 5 smallest prime numbers are 1, 2, 3, 5, and 7.

So when multiplied it equals 105.

Divide by 42 and you get 2 21/42

So you have a remainder of 21

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Use substitution to solve the system of equations. y + x = 3 y = 1.5x + 1

jeyben [28]

Answer:

x=0.8, y=2.2 (0.8, 2.2).

Step-by-step explanation:

y+x=3

y=1.5x+1

-------------

1.5x+1+x=3

2.5x=3-1

2.5x=2

x=2/2.5

x=0.8

y+0.8=3

y=3-0.8

y=2.2

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3 years ago

PLZ EXPLAIN. what is the area of this figure?

BlackZzzverrR [31]

The area of this figure is 532m.

First you do the square which is 18 time 18 gets you 324m.

The for the first triangle you would do 18 times 16 then divide by 2 which is 144m.

For the last triangle you would do 16•8 div by 2 which will give you 64m.

Add them all up and you get 532m.

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3 years ago

What two numbers add up to 6 and multiply to 12?

GuDViN [60]

Erm

x+y=6
xy=12

x+y=6
y=6-x
sub back

xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
$x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}$

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i

$x= \frac{-(-6)+/- \sqrt{(-6)^2-4(1)(12)} }{2(1)}$
$x= \frac{6+/- \sqrt{36-48} }{2}$
$x= \frac{6+/- \sqrt{-12} }{2}$
$x= \frac{6+/- (\sqrt{-1})(\sqrt{12}) }{2}$
$x= \frac{6+/- (i)(2\sqrt{3}) }{2}$
$x= \frac{6+/- 2i\sqrt{3} }{2}$
x=3+/-i√3

the numbers are 3+i√3 and 3-i√3
no real numbers tho

7 0

3 years ago

sam said the absoulute value of 14 is -14. Kai said the absolute value of 14 is 14. Who is correct. Explain

Hoochie [10]

Answer:

Kai is right.

Step-by-step explanation:

Absolute Value is always positive.

4 0

3 years ago

Bag A contains 3 red and 2 white marbles

Paladinen [302]

Your question is incomplete.

If you want me to tell the ratio, its 3:2

4 0

3 years ago