3 years ago

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

1 answer:

7 0

Answer:

Step-by-step explanation:

The 5 smallest prime numbers are 1, 2, 3, 5, and 7.

So when multiplied it equals 105.

Divide by 42 and you get 2 21/42

So you have a remainder of 21

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